StackOverflow2013

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20453016
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2013-12-08T11:45:25.850
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2013-12-08T11:45:25.850
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<pre><code>handler myhandler; </code></pre> That creates an object. If it's inside a function, then it has automatic storage duration, and will be destroyed automatically when it goes out of scope. If it's outside a function, then it has static storage duration, and will be destroyed automatically at the end of the program. <pre><code>handler myhandler=new handler(); </code></pre> That probably doesn't compile; unless <code>handler</code> has a strange constructor allowing implicit conversion from a pointer, in which case it does something strange. <pre><code>handler *myhandler; </code></pre> That declares a pointer, which could be used to refer to an object of type <code>handler</code>. It doesn't create an object, nor does it point to any object yet. <pre><code>handler *myhandler=new handler(); </code></pre> That creates a dynamic object, and initialises a pointer to point to it. This is usually a bad idea, since it's likely to lead to a memory leak (or worse) when you fail to delete it correctly. Don't create dynamic objects unless you really need them to outlive the current scope; and use a smart pointer when you do need to: <pre><code>auto myhandler = std::make_unique<handler>(); // C++14 std::unique_ptr<handler> myhandler(new handler); // C++11 </code></pre> If you really want to juggle a raw pointer for educational purposes, then remember to delete the object once you've finished with it: <pre><code>delete myhandler; </code></pre> and take special care to make sure this only happens once, and happens even if an exception is thrown.
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1. PODifference in syntaxes of making objects in C++
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1. USMike Seymour
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