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POHow to decode Rijndael in ruby (encoded in VB.net)
 

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  1. POHow to decode Rijndael in ruby (encoded in VB.net)
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    <p>I am using Rinjael to encode in VB.NET and need to decode in Ruby. My VB.NET encryption class looks like this:</p> <pre><code>Private Class Encryptor Private symmetricKey As System.Security.Cryptography.RijndaelManaged Private iVector As Byte() Private Key As Byte() Public Function encrypt(ByVal data As String) As String Try Dim plainTextBytes As Byte() = System.Text.Encoding.ASCII.GetBytes(data) Dim encryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateEncryptor(Key, iVector) Dim memoryStream As New System.IO.MemoryStream Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, encryptor, System.Security.Cryptography.CryptoStreamMode.Write) cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length) cryptoStream.FlushFinalBlock() Dim cipherTextBytes As Byte() = memoryStream.ToArray() memoryStream.Close() cryptoStream.Close() Return Convert.ToBase64String(cipherTextBytes) Catch Return "" End Try End Function Public Function decrypt(ByVal data As String) As String Try Dim crypted As Byte() = Convert.FromBase64String(data) Dim decryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateDecryptor(Key, iVector) Dim memoryStream As New System.IO.MemoryStream(crypted) Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, decryptor, System.Security.Cryptography.CryptoStreamMode.Read) Dim plain(crypted.Length) As Byte Dim count As Integer = cryptoStream.Read(plain, 0, plain.Length) memoryStream.Close() cryptoStream.Close() Return System.Text.Encoding.UTF8.GetString(plain, 0, count) Catch Return "" End Try End Function Public Sub New(ByVal clientkey As String) iVector = System.Text.Encoding.ASCII.GetBytes("1234567890123456") Key = System.Text.Encoding.ASCII.GetBytes(clientkey) symmetricKey = New System.Security.Cryptography.RijndaelManaged symmetricKey.Mode = System.Security.Cryptography.CipherMode.CBC End Sub End Class </code></pre> <p>this works ok and I am able to decrypt in java using the AES/CBC/PKCS5Padding. Now, my password and iv are 16 characters long (16*16bit = 256). When I try to decrypt in Ruby, it complains that my password is to short... I assume that it is using 8bit chars. I use this class for decryption in ruby:</p> <pre><code> require 'openssl' module Crypt # Decrypts a block of data (encrypted_data) given an encryption key # and an initialization vector (iv). Keys, iv's, and the data # returned are all binary strings. Cipher_type should be # "AES-256-CBC", "AES-256-ECB", or any of the cipher types # supported by OpenSSL. Pass nil for the iv if the encryption type # doesn't use iv's (like ECB). #:return: =&gt; String #:arg: encrypted_data =&gt; String #:arg: key =&gt; String #:arg: iv =&gt; String #:arg: cipher_type =&gt; String def Crypt.decrypt(encrypted_data, key, iv, cipher_type) aes = OpenSSL::Cipher::Cipher.new(cipher_type) aes.decrypt aes.key = key aes.iv = iv if iv != nil aes.update(encrypted_data) + aes.final end # Encrypts a block of data given an encryption key and an # initialization vector (iv). Keys, iv's, and the data returned # are all binary strings. Cipher_type should be "AES-256-CBC", # "AES-256-ECB", or any of the cipher types supported by OpenSSL. # Pass nil for the iv if the encryption type doesn't use iv's (like # ECB). #:return: =&gt; String #:arg: data =&gt; String #:arg: key =&gt; String #:arg: iv =&gt; String #:arg: cipher_type =&gt; String def Crypt.encrypt(data, key, iv, cipher_type) aes = OpenSSL::Cipher::Cipher.new(cipher_type) aes.encrypt aes.key = key aes.iv = iv if iv != nil aes.update(data) + aes.final end end </code></pre> <p>Now. By trying to decrypt using Crypt.decrypt(data,key,iv, "AES-CBC-256") i am certain that preliminary string/byte transformations have to be done on my data,key,iv to work correctly.</p> <p>How shall I call Crypt.decrypt using key = "passwordpassword" and iv="1234567890123456"? Do I need to base64 decode my data?</p> <p>Here's my decryption call, which doesn't seem to work (trying padding with zeroes):</p> <pre><code> text = Base64.decode64(text) pass = Digest::SHA1.hexdigest("#{@pass}0000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32) iv = Digest::SHA1.hexdigest("12345678901234560000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32) return Crypt.decrypt(text,pass,iv,"AES-256-CBC") </code></pre>
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