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POAccept only a letter input
 

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  1. POAccept only a letter input
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    <p>I'm working on error handling my hangman program. I want to print out an error message if the user inputs a number (int/double) instead of a letter (char/string). How do I do that?</p> <p>This is the code for the engine class:</p> <pre><code>//hangman viewer stuff ////////////////////////////////////////////////////////////// JFrame frame = new JFrame(); frame.setSize(200,375); //invoked the method setSize on the implicit parameter frame frame.setTitle("Hangman"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); HangmanComponent g = new HangmanComponent(); frame.add(g); frame.setVisible(true); /////////////////////////////////////////////////////////////// String wordd = JOptionPane.showInputDialog("Type in a word."); int length = wordd.length(); String blank = "_ "; String word2 = new String(""); int guesscount = 10; ArrayList&lt;String&gt;answers=new ArrayList&lt;String&gt;(); //creates reference to empty structure that will contain references char blanks[]=new char[wordd.length()]; //creates an array with the same number of terms as the length of the word for (int i=0; i&lt;length; i++)//fills the array with blanks corresponding to the length of the word { blanks[i] = '_'; } HangmanComponent y = new HangmanComponent(); while (true) { String letter = JOptionPane.showInputDialog("Guess a letter! You have "+guesscount+" guesses."+"\n"+answers+"\n"+Arrays.toString(blanks).replace(",", " ").replace("[","").replace("]","")); //Prints a space char letterchar = letter.charAt(0); //converts string letter to char letterchar int idx = 0; boolean found = false; answers.add(letter); //adds the string to the arraylist answers while (idx &gt;= 0 &amp;&amp; idx &lt; length) //idx is greater than or equal to 0 but less than the length of the word { //System.out.println("idx = " + idx); idx = wordd.indexOf(letter, idx); //idx is the index of "letter" in "wordd" and finds all instances of the letter //System.out.println("idx = " + idx + ", guesscount = " + guesscount); if (idx != -1) //if idx is not -1 (the letter exists in the word) { found = true; blanks[idx] = letterchar; //sets the term in the array equal to the letter idx += 1; //idx=idx+1 } else { guesscount=guesscount-1; y.nextStage(); y.printStage(); frame.add(y); frame.setVisible(true); break; } } if (found) { JOptionPane.showMessageDialog(null, Arrays.toString(blanks).replace(",", " ").replace("[","").replace("]","")+"\n"+"You found a letter!"+"\n"+answers); } else { JOptionPane.showMessageDialog(null, Arrays.toString(blanks).replace(",", " ").replace("[","").replace("]","")+"\n"+"That letter is not in the word! Guess again!"+"\n"+answers); if (guesscount == 0) { JOptionPane.showMessageDialog(null, "Sorry, you're all out of guesses. The answer was '"+wordd+".' Thanks for playing!"); break; } } char [] lettersArray = wordd.toCharArray(); //converts word to array of chars if (Arrays.equals(blanks, lettersArray))//compares array of blanks to array of letters { JOptionPane.showMessageDialog(null, "You guessed the word! Thanks for playing!"); break; } } </code></pre> <p>}</p>
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      1. PTAnswer
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    1. USuser2963365
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      1. POAccept only a letter input
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      1. VTUpMod
    1. COShow your code.
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      1. USMasudul
    2. COOut of curiosity is this all written in the main function?
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      1. UStheGreenCabbage
    3. COYou could create an array of acceptable characters, and a method that sorts through that and checks if a variable (whatever the input is) is equal to any of them; if not, throw an error and stop the program or ask them again for a correct character (using a while loop, supposedly). This is how I would do it, albeit I've only done this using Ruby, never tried in Java. There are probably many better ways to automatically check, but I don't know.
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      1. POAccept only a letter input
      1. USIHazABone
 

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