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PORemoving all non-unique letters from a char [] array for hangman
 

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  1. PORemoving all non-unique letters from a char [] array for hangman
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    <p>I am having trouble understanding how to remove a letter from a char array here is my code </p> <pre><code>import java.util.Random; import java.util.Scanner; public class Main { public static void main(String [] args) { start(); } public static void start() { Scanner scan = new Scanner(System.in); Random rand = new Random(); String [] Words = {"Dog","cat","Food","Bacon","Turkey","hood","poo","Good","look"}; String RandomWord = Words[rand.nextInt(Words.length)]; char [] array = RandomWord.toCharArray(); boolean [] parrallelArray = new boolean[array.length]; int i = 0; int placeholder = 0; System.out.println(findUniqueLetters(array)); char input = 0; while(i&lt;findUniqueLetters(array)){ i++; System.out.println("You have a "+RandomWord.length()+" Word "+RandomWord); System.out.println("Guess a letter : "); input = scan.next().charAt(0); for(int j = placeholder; j&lt;array.length;j++){ if(input == array[j]){ j++; placeholder = j; System.out.println("You got it right"); break; } else if(!(input ==array[j])){ j++; placeholder = j; System.out.println("You got it wrong"); break; } } } System.out.println("You have wasted all your tries!"); } public static int findUniqueLetters(char [] a){ int Unique = 1; for(int i = 1; i&lt;a.length;i++){ if(!(a[i] == a[i-1])){ Unique++; } } return Unique; } } </code></pre> <p>Is there another way to do this or is deleting it the only way to do this? I have tried to switch the repeated letter in the array with the non repeated one in the array but that only works for some words.</p>
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    1. USuser3000477
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    1. COyou might want to check out http://stackoverflow.com/questions/12632167/removing-duplicates-from-array-in-java if you only want unique alphabets in your array
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      1. PORemoving all non-unique letters from a char [] array for hangman
      1. USVineet Kosaraju
    2. COThe loop is already doing `j++`, why are you doing it again inside the loop?
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      1. USPaul Samsotha
    3. CObecause I am breaking the loop so I need to come back and ask the question again and I cant do that withought the while loop
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      1. USuser3000477
 

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