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POArray programming - check winner in a Tic Tac Toe game for an nxn board with n players
 

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  1. POArray programming - check winner in a Tic Tac Toe game for an nxn board with n players
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    <p>I am making a tic tac toe game for n number of players on a nxn board, but the winning condition is aways 3 on a row. My so far solution to the problem is: when a move is made the program will check the following square for 3 on a row.</p> <pre><code>(x-1,y+1) (x,y+1) (x+1,y+1) (x-1,y) (x,y) (x+1,y) (x-1,y-1) (x,y-1) (x+1,y-1) </code></pre> <p>It will check the top (x-1,y+1) (x,y+1) (x+1,y+1) bottom(x-1,y-1) (x,y-1) (x+1,y-1) sides(x+1,y+1) (x+1,y) (x+1,y-1) , (x-1,y+1) (x-1,y) (x-1,y-1) , the diagonals and the ones going through the middle(x,y).</p> <p>my code so far is:</p> <pre><code> public int checkWinning() { for(int a = 1; a &lt; size-1; a++){ for(int b = 1; b &lt; size-1; b++){ if (board[a][b] == board[a+1][b] &amp;&amp; board[a][b] == board[a-1][b]){ return board[a][b]; }else if(board[a][b] == board[a][b+1] &amp;&amp; board[a][b] == board[a][b-1]){ return board[a][b]; }else if(board[a][b] == board[a+1][b-1] &amp;&amp; board[a][b] == board[a-1][b+1]){ return board[a][b]; }else if(board[a][b] == board[a+1][b+1] &amp;&amp; board[a][b] == board[a-1][b-1]){ return board[a][b]; } } } for(int d = 1; d &lt; size-1; d++){ if (board[0][d] == board[0][d-1] &amp;&amp; board[0][d] == board[0][d+1]){ return board[0][d]; } else if (board[size-1][d] == board[size-1][d-1] &amp;&amp; board[size-1][d] == board[size-1][d+1]){ return board[size-1][d]; } } for(int c = 1; c &lt; size-1; c++){ if (board[c][0] == board[c-1][0] &amp;&amp; board[c][0] == board[c+1][0]){ return board[c][0]; }else if(board[c][size-1] == board[c-1][size-1] &amp;&amp; board[c][size-1] == board[c+1][size-1]){ return board[c][size-1]; } } return 0; } </code></pre> <p>where the first section is where I check the ones through the middle and diagonals. the second section I check the top an bottom and the top and the thrid section checks the sides. </p> <p>When it returns 0 is means that there are no winner yet.</p> <pre><code>@override public void checkResult() { int winner = this.board.checkWinning(); if (winner &gt; 0) { this.ui.showResult("Player "+winner+" wins!"); } if (this.board.checkFull()) { this.ui.showResult("This is a DRAW!"); } } </code></pre> <p>Board[x][y] -> 2-dimensional array representing the board, The coordinates are counted from top-left (0,0) to bottom-right (size-1, size-1), board[x][y] == 0 signifies free at position (x,y), board[x][y] == i for i > 0 signifies that Player i made a move on (x,y), just so you know it.</p> <p>my problem is that when i expands the board to a size larger than 3x3 the program somehow overwrites it self or a does not check every thing sides top and bottom every time, and I can't seem too se why.</p>
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