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    <p>According to <a href="http://perldoc.perl.org/Time/HiRes.html#gettimeofday-%28%29" rel="nofollow">this documentation</a>, the <code>gettimeofday</code> function returns seconds or microseconds since the unix epoch, which is 1/1/1970 <strong>UTC</strong>. Because it is in UTC, it is not affected by time zones at all.</p> <p>Also, in your original code you are just using <code>gettimeofday</code>, which is going to be returning timestamps from <em>now</em>, not from 1970. But in your suggested answer, for some reason, you have hard-set the timestamp, which won't help you do much.</p> <p>Yes, there is history to just about every time zone, including Singapore. <a href="https://github.com/eggert/tz/blob/master/asia#L2416-2429" rel="nofollow">You can see it in the TZDB here</a>. But you are incorrect about it being +8:30 at the epoch. It was actually +7:30. <a href="http://www.timeanddate.com/worldclock/converted.html?iso=19700101T00&amp;p1=185&amp;p2=236" rel="nofollow">You can verify also on this site</a>. But it doesn't matter anyway because like I said, <code>gettimeofday</code> works strictly in UTC.</p> <p>I think the problem is in how you are interpreting the results. You have as your last line:</p> <pre><code>print STDOUT $time{'mm:ss.mmm', $stat_perf} . " \n"; </code></pre> <p>But <code>$stat_perf</code> is the elapsed duration of time, not a value that you can treat as a timestamp. You probably shouldn't be passing it to <code>$time</code>, since that <em>will</em> use the local time zone and be expecting a full timestamp.</p> <p>Also, you may want to use <code>tv_interval</code>, as shown <a href="http://perldoc.perl.org/Time/HiRes.html#EXAMPLES" rel="nofollow">in the examples</a>.</p> <h3>Update</h3> <p>I searched through the CPAN archives and I'm sure somewhere there is a module for formatting an elapsed duration of time, but I can't seem to find it. Anyway, it's not too hard to write this on your own. Here, this should work:</p> <pre><code>my $min = $stat_perf / 60; my $sec = ($stat_perf * 1000 % 60000) / 1000; my $elapsed = sprintf("%02u:%06.3f", $min, $sec); print STDOUT $elapsed . "\n"; </code></pre>
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    1. POComputing small time differences in Singapore adds 30 minutes when converted to hh:mm:ss.mmm
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    1. USMatt Johnson
    1. USMatt Johnson
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    1. COI don't think you're getting what is the problem I have to solve: I need to have a string representing minutes, seconds and microseconds of sometime very short times. `gettimeofday` provides me the desired level of granularity. `tv_interval` doesn't do conversion to string in sexagesimal format. Until I'm wrong, `$time{}` gets me the job done. Still, in Singapore, whatever the method I use to get that elapsed time; `print STDOUT $time{'mm:ss.mmm',0};` yields `30:00.000`. `gettimeofday` is not involved here.
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    2. COAs you pointed out, `$time{}` handles it as a timestamp. Nothing new; hence the trick I posted. So far I've not found a better way of getting - anywhere on the planet - 67.934 seconds converted into "01:07.934". Any suggestion?
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    3. COI'll look to see if I can find (or write) a script for emitting an elapsed time formatted in that format. But do realize that by treating it as a time of day you've also got a problem that a value like 65 minutes is going to be treated as 1 hour and 5 minutes, and since you're not showing hours, you will just see 5 minutes.
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