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    <p>What about this:</p> <pre><code>import fileinput for line in fileinput.input(): print(line.split()) </code></pre> <p>You can try it like that:</p> <pre><code>lsof | python your_script.py </code></pre> <p><strong>Addressing the 'spaces in <em>NAME</em> problem'</strong></p> <p>For addressing the issue about possible spaces in <em>NAME</em> column mentioned in the comments I can propose the following solution. It's based on my desire to keep it simple and on the fact that only the last column could have spaces. </p> <p>The algorithm is simple: 1. Find the position where the last columns start - I use the header <em>NAME</em> starting position 2. Cut the line after that position> What you just cut is the value of the <em>NAME</em> column 3. <em>split()</em> the rest of the line. </p> <p>Here is the code:</p> <pre><code>import fileinput header_limits = dict() records = list() input = fileinput.input() header_line = None for line in input: if not header_line: header_line = line col_names = header_line.split() for col_name in col_names: header_limits[col_name] = header_line.find(col_name) continue else: record = dict() record['NAME'] = line[header_limits['NAME']:].strip() line = line[:header_limits['NAME'] - 1] record.update(zip(col_names, line.split())) records.append(record) for record in records: print "%s\n" % repr(record) </code></pre> <p>The result is a list of dictionaries. Every dictionary correspond to one line of the <em>lsof</em> output.</p> <p>This is interesting task showing the power of python for everyday tasks. </p> <p>Any way, if it's possible I would prefer the use of some python library as the proposed <em>psutils</em></p>
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