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POHow group the employees in ranges of hours?
 

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  1. POHow group the employees in ranges of hours?
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    <p>I have this table to save the time the employees spend doing a routine task.</p> <pre><code>CREATE TABLE tasks ( id INT NOT NULL PRIMARY KEY, name VARCHAR(100), date_task date, time_ini time, time_end time ); </code></pre> <ul> <li>I'm trying to group the employees who have at least two time_ini's with a difference &lt; 15 minutes with any employee's time_ini or time_end.</li> <li>If none of their time_inis meet this condition, then this employee would be grouped alone.</li> <li>The groups will be numbered from 1 to n. </li> <li>And then the groups will be ordered by date ascending, and time_ini ascending.</li> </ul> <p>This is an example of data:</p> <pre><code>(1, "oscar", '2012-01-01', '01:30', '01:32'), (2, "oscar", '2012-01-01', '02:30', '02:32'), (3, "oscar", '2012-01-01', '05:30', '05:32'), (4, "oscar", '2012-01-01', '06:30', '06:32'), (5, "mario", '2012-01-01', '02:43', '02:43'), (6, "mario", '2012-01-01', '02:53', '02:53'), (7, "mario", '2012-01-01', '05:30', '05:30'), (8, "martah", '2012-01-01', '01:25', '01:28'), (9, "martah", '2012-01-01', '02:29', '02:41'), (10, "jesus", '2012-01-01', '01:25', '01:28'), (11, "jesus", '2012-01-01', '01:25', '02:28'), (12, "jesus", '2012-01-01', '07:33', '08:32'), (13, "jesus", '2012-01-01', '07:35', '07:36'), (14, "jesus", '2012-01-01', '08:36', '08:39'), (15, "rober", '2012-01-01', '02:43', '02:46'), (16, "rober", '2012-01-01', '02:56', '03:00'), (17, "rober", '2012-01-01', '02:29', '11:32'), (18, "pedro", '2012-01-01', '11:36', '12:46'), (19, "pedro", '2012-01-01', '12:36', '16:46'); </code></pre> <p>This would be the result:</p> <pre><code>GROUP NAME 1 oscar 1 marta 1 jesus 2 mario 2 rober 3 pedro </code></pre> <p>I came up with something like this:</p> <pre><code>select distinct a.name from tasks a where (select count(id) from tasks b where ( MINUTE(TIMEDIFF(a.time_ini, b.time_ini)) &lt; 15 OR MINUTE(TIMEDIFF(a.time_end, b.time_ini)) &lt; 15 ) and b.name &lt;&gt; a.name) &gt;= 2; </code></pre> <p>I'm afraid I can't group them this way, but I think I'm not too far to the solution, isn't it? </p> <p>Any idea, tip or advice will be appreciated, and if you need more info, let me know and I'll edit the post. Is little bit hard to explain...</p>
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      1. POHow group the employees in ranges of hours?
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    1. COIs it always the case that a.date_end - a.date_ini < 30 minutes? And I note that date_end is not always > date_ini !?! Oh, and can tasks overlap dates?
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      1. USStrawberry
    2. COThe difference between time_end and time_ini won't be always 30 mins. I built this data only for the example. And time_end must be >= time_ini, sorry, I've edited the post. And tasks can't overlap dates. Thanks for your interest.
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    3. COSo, if I've got this right then really you're interested in any time_ini that occurs "BETWEEN x.time_ini - 15 INTERVAL 15 MINUTE AND x.time_end + INTERVAL 15 MINUTE", right?
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