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POWrite a function that takes two lists, and returns True if the first list is the reverse of the same elements in the second list, and False otherwise
 

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  1. POWrite a function that takes two lists, and returns True if the first list is the reverse of the same elements in the second list, and False otherwise
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    <p>This is the code that I have written so far for Python. When I write <code>b[len(b)-1]</code>: it gives me the last number of the b list and accordingly when I put <code>a[0]</code> it gives me the first element (Sorry if this seems obvious, I'm trying to explain in detail what I am trying to do and what I understand of the code so I can get better help). <code>b[len(b)-i]</code> -- My mentality for this part of my code is that I want to increase i by 1. </p> <p>For example: <code>b[len(b)-1]</code> <code>b[len(b)-2]</code> <code>b[len(b)-3]</code> etc. </p> <p>Similarly, I want to keep increase a by i <code>a[0]</code> <code>a[1]</code> <code>a[2]</code></p> <p>How would I go about on fixing my code? Any help will be appreciated! Thank you in advance!</p> <pre><code>def isReverse(a,b): if len(a)==len(b): #print True for i in a and b: if b[len(b)-i] == a[0+i]: print True elif len(a)!=len(b): print False </code></pre>
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    1. USuser3055848
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    1. COReturning isn't the same as printing, that much is for sure. That much alone needs to be fixed.
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      1. USMakoto
    2. CO`def isReverse(a,b): return a==b[::-1]`
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    3. CO`[::-1]` is the only trick you need here. Remember that the 3rd argument taken is the step. If it's `-1`, it reverses the whole string. This is basically the way to check a palindrome or similar things. ;)
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