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POTrouble getting array back from JSON call to SQL
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20256422
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2013-11-28T01:57:36.877
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2013-11-28T02:09:18.687
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2013-11-28T02:09:18.687
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Just trying to grab everything from a table "guesses" sorted by "cnt" and turn it into a javascript array. Can't get it to give me anything I can work with, though. PHP file: <pre><code><?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $dbname = 'words'; $dbtable = 'guesses'; //------ DATABASE CONNECTION --------// mysql_connect($dbhost,$dbuser,$dbpass) or die ("Unable to connect to database"); mysql_select_db($dbname) or die ("Unable to select database"); $sql = "SELECT * FROM $dbtable ORDER BY cnt ASC"; $result = mysql_query($sql); while($array = mysql_fetch_assoc($result)) { echo json_encode($array); } ?> </code></pre> JavaScript: <pre><code> $.getJSON('grab.php', function(response) { // response is a JSON object that contains all the info from sql query // tried so much stuff here... no avail. console.log(response); }) </code></pre> The console doesn't say anything. "SELECT * FROM guesses ORDER BY cnt ASC" in the phpmyadmin console DOES return the correct entries and order. EDIT: I've also tried <pre><code><?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $dbname = 'words'; $dbtable = 'guesses'; //------ DATABASE CONNECTION --------// mysql_connect($dbhost,$dbuser,$dbpass) or die ("Unable to connect to database"); mysql_select_db($dbname) or die ("Unable to select database"); $sql = "SELECT * FROM $dbtable ORDER BY cnt ASC"; $result = mysql_query($sql); while($array = mysql_fetch_assoc($result)); echo json_encode($array); ?> </code></pre> Which might be syntactically better(???) but it returns "false" to console, and nothing else.
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<javascript><php><mysql><sql><json>
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Trouble getting array back from JSON call to SQL
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