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POhow to do function pointer like in C++, but for variable
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2013-11-27T16:53:22.677
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sorry for the title, it's quite confusing to explain, but it will be more clear with example In C, I used to write program like this : <pre><code>void createClassA() { } void createClassB() { } typedef struct { const char *name; void (*create_class)(); } MapList; MapList mapList[] = { {"A", &createClassA}, {"B", &createClassB }, }; void create(const char *name) { int i=0; for (i=0; i < sizeof(mapList) / sizeof(MapList); i++) { if (strcmp(name, mapList[i].name) == 0) mapList[i].create_class(); } } int main(int argc, char** argv) { if (argc < 1) return -1; create(argv[1]); return 0; } </code></pre> So if I have more types, all I have to do is to create the function itself and add it to the mapList. but in C++, the best I can do is something like: <pre><code>#include <iostream> class myA{}; class myB{}; class myC{}; class Base { public: template<class T> void createClass() { T* t = new T(); //t->doSomethingUseful(); } void create(const std::string name) { if (name=="A") createClass<myA>(); else if (name=="B") createClass<myB>(); else if (name=="C") createClass<myC>(); } }; int main(int agrc, char** argv) { if (argc<1) return -1; Base b; b.create(argv[0]); return 0; } </code></pre> Can I create something like : <pre><code>typedef struct { std::string name; [CLASS_TYPE] class_type; <== I don't know how } MapList; </code></pre> so I can create a mapping List but fill it with class Type, something like <pre><code>mapList[] = { {"A", myA}, {"B", myB}, {"B", myC}, }; </code></pre> and then I can create iteration like: <pre><code>for (int i=0; i<sizeof(mapList) / sizeof(MapList); i++) { if (mapList[i].name == name) b.createClass<mapList[i].classType>(); } </code></pre> Thanks guys :)
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how to do function pointer like in C++, but for variable
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