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  1. PO
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    <p>use:</p> <pre><code>SELECT DISTINCT </code></pre> <p>instead of:</p> <pre><code>SELECT </code></pre> <p>or GROUP BY statement.</p> <p>-- EDIT --</p> <p>Example echo:</p> <pre><code>$result = $db-&gt;query("SELECT client.*, GROUP_CONCAT(sys_notes.note SEPARATOR "|") as note, sys_notes.* FROM client LEFT JOIN sys_notes ON sys_notes.client_id = client.id GROUP BY sys_notes.client_id ORDER BY create_date DESC"); ob_start(); ?&gt; &lt;div class="content"&gt; &lt;?php foreach($result as $row) { sprintf("&lt;p&gt;%s %s&lt;br /&gt;%s&lt;br /&gt;%s&lt;/p&gt; %s &lt;ul&gt;", $row['firstname'], $row['lastname'], $row['role'], $row['desc'](example)); foreach(explode("|", $row['note']) as $note) { sprintf("&lt;li&gt;%s&lt;/li&gt;", $note); } sprintf("&lt;/ul&gt;"); } ?&gt; &lt;/div&gt; &lt;? $result = ob_end_clean(); echo $result; </code></pre> <p>-- FINAL UPDATE --</p> <pre><code>&lt;?php try { $db = new PDO($dsn, $user, $password); } catch (PDOException $e) { echo 'Connection failed: ' . $e-&gt;getMessage(); } $result = $db-&gt;query('SELECT client . * , GROUP_CONCAT( sys_notes.note SEPARATOR "|" ) AS n, sys_notes.* FROM client LEFT JOIN sys_notes ON sys_notes.client_id = client.id GROUP BY sys_notes.client_id ORDER BY create_date DESC'); ob_start(); ?&gt; &lt;div class="content"&gt; &lt;?php foreach($result as $row) { printf("&lt;p&gt;%s %s&lt;br /&gt;%s&lt;/p&gt; %s &lt;ul&gt;", $row['first_name'], $row['last_name'], $row['issue'], $row['other']); foreach(explode("|", $row['n']) as $note) { printf("&lt;li&gt;%s&lt;/li&gt;", $note); } printf("&lt;/ul&gt;"); } ?&gt; &lt;/div&gt; &lt;?php ob_end_flush(); </code></pre>
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    1. POCombine two tables and echo out the result (PHP MYSQL)
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    1. PTAnswer
    1. USLashus
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    1. This table or related slice is empty.
    1. POCombine two tables and echo out the result (PHP MYSQL)
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    1. VO
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    1. COcan you explain a bit more? How would i then echo it out to get the result as described over?
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      1. USmikswe
    2. COJust loop the result and echo certain rows like echo $row['note'];
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      1. USLashus
    3. COhi, i´ve studying your suggestion and I understand what we are doing, at least thats good! =). I´ve tried this, but the output is only "1". Literally just: 1 (which is the first id (AI) in sys_notes...). Can you help me a bit more, i really appreciate your helping out here - thanks!
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