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    <p>To change back human readable format, you can also use Geocoder but that is not working sometimes because google play service problem. I used this json geocodeing as second option for in case.</p> <p>Please refer <a href="https://developers.google.com/maps/documentation/geocoding/">Google Geocoding API</a></p> <p>Workflow is pass your latitude and longitude and get current location. Request url gonna be like this.</p> <pre><code>String reqURL = "http://maps.googleapis.com/maps/api/geocode/json?latlng="+ lat+","+lng +"&amp;sensor=true"; </code></pre> <p>Hopefully, this answer will help you.</p> <pre><code>public static JSONObject getLocationInfo(double lat, double lng) { HttpGet httpGet = new HttpGet("http://maps.googleapis.com/maps/api/geocode/json?latlng="+ lat+","+lng +"&amp;sensor=true"); HttpClient client = new DefaultHttpClient(); HttpResponse response; StringBuilder stringBuilder = new StringBuilder(); try { response = client.execute(httpGet); HttpEntity entity = response.getEntity(); InputStream stream = entity.getContent(); int b; while ((b = stream.read()) != -1) { stringBuilder.append((char) b); } } catch (ClientProtocolException e) { } catch (IOException e) { } JSONObject jsonObject = new JSONObject(); try { jsonObject = new JSONObject(stringBuilder.toString()); } catch (JSONException e) { e.printStackTrace(); } return jsonObject; } public static String getCurrentLocationViaJSON(double lat, double lng) { JSONObject jsonObj = getLocationInfo(lat, lng); Log.i("JSON string =&gt;", jsonObj.toString()); String currentLocation = "testing"; String street_address = null; String postal_code = null; try { String status = jsonObj.getString("status").toString(); Log.i("status", status); if(status.equalsIgnoreCase("OK")){ JSONArray results = jsonObj.getJSONArray("results"); int i = 0; Log.i("i", i+ "," + results.length() ); //TODO delete this do{ JSONObject r = results.getJSONObject(i); JSONArray typesArray = r.getJSONArray("types"); String types = typesArray.getString(0); if(types.equalsIgnoreCase("street_address")){ street_address = r.getString("formatted_address").split(",")[0]; Log.i("street_address", street_address); }else if(types.equalsIgnoreCase("postal_code")){ postal_code = r.getString("formatted_address"); Log.i("postal_code", postal_code); } if(street_address!=null &amp;&amp; postal_code!=null){ currentLocation = street_address + "," + postal_code; Log.i("Current Location =&gt;", currentLocation); //Delete this i = results.length(); } i++; }while(i&lt;results.length()); Log.i("JSON Geo Locatoin =&gt;", currentLocation); return currentLocation; } } catch (JSONException e) { Log.e("testing","Failed to load JSON"); e.printStackTrace(); } return null; } </code></pre> <p>As my experience, <strong>only device generated latitude and longitude</strong> will work. Then call </p> <pre><code>String currentLocation = getCurrentLocationViaJSON(lat, lng); </code></pre>
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    1. POGet current location using json
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    1. POGet current location using json
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    1. COthank u..yeah i tried gecoder i have the same issue some tie i have to restart the device to get the address.i am new to json so it would be very helpful iy you are providing some sample tutorial link or code snippet.Once again thank u for your help..
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    2. COThis is how to handle json response http://www.androidhive.info/2012/01/android-json-parsing-tutorial/ Good luck !
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    3. COPlease refer my answer back. I edited.
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