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POModelForeign key fails to create a column id linked to the object in Django
 

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  1. POModelForeign key fails to create a column id linked to the object in Django
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    <p>I can't figure out why the <code>ForeignKey</code> is not working in my <code>models.py</code>. </p> <p>I closely followed the tutorial and all I need to do is to make <code>Games</code> a part of <code>Department</code> (same with <code>Choices</code> and part of the <code>Poll</code>). Same games can be part of different departments. </p> <p>Here's the code for my <code>models.py</code>:</p> <pre><code>from django.db import models class Department(models.Model): name = models.CharField(max_length=200) def __unicode__(self): return self.name class Game(models.Model): department = models.ForeignKey(Department) name_of_the_game = models.CharField(max_length=200) def __unicode__(self): return self.name_of_the_game </code></pre> <p>I created the SQLite tables and did everything like in the tutorial. </p> <p>This is the error that it gives me in python shell: </p> <pre><code>&gt;&gt;&gt; from logins.models import Department, Game &gt;&gt;&gt; p = Department.objects.get(pk = 1) &gt;&gt;&gt; p.game_set.all() Traceback (most recent call last): File "&lt;console&gt;", line 1, in &lt;module&gt; File "/Library/Python/2.7/site-packages/django/db/models/query.py", line 71, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/Library/Python/2.7/site-packages/django/db/models/query.py", line 96, in __iter__ self._fetch_all() File "/Library/Python/2.7/site-packages/django/db/models/query.py", line 854, in _fetch_all self._result_cache = list(self.iterator()) File "/Library/Python/2.7/site-packages/django/db/models/query.py", line 220, in iterator for row in compiler.results_iter(): File "/Library/Python/2.7/site-packages/django/db/models/sql/compiler.py", line 710, in results_iter for rows in self.execute_sql(MULTI): File "/Library/Python/2.7/site-packages/django/db/models/sql/compiler.py", line 781, in execute_sql cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/util.py", line 69, in execute return super(CursorDebugWrapper, self).execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/util.py", line 53, in execute return self.cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/utils.py", line 99, in __exit__ six.reraise(dj_exc_type, dj_exc_value, traceback) File "/Library/Python/2.7/site-packages/django/db/backends/util.py", line 53, in execute return self.cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/sqlite3/base.py", line 450, in execute return Database.Cursor.execute(self, query, params) OperationalError: no such column: logins_game.department_id </code></pre> <p>Maybe I am just missing some very basic step, but even after reading related docs on Django site, I can't seem to figure it out. </p>
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    1. USJ. Ghyllebert
    1. USlulu
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    1. COHow did you create your tables? syncdb? Can it be that you added foreign key after you performed syncdb?
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      1. USdragoon
    2. COYes, I did create it! And I did it before I made the foreignKeys =, thats why I am confused :/
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      1. POModelForeign key fails to create a column id linked to the object in Django
      1. USlulu
    3. COSo, if you don't have any data in the tables, I suggest you to delete them and run syncdb again. In a long term I suggest you to use South as @krs said. http://south.readthedocs.org/en/latest/
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      1. POModelForeign key fails to create a column id linked to the object in Django
      1. USdragoon
 

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