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    <p>I'm not entirely sure of your question.<br /> Are you simply trying to fill an array with lines of a file?<br /> That is simple and this will do it:</p> <pre><code>int[] mArray = File.ReadAllLines("pathAndFilename").Select(x =&gt; int.Parse(x)).ToArray(); </code></pre> <p>Is that sufficient? If not, then please clarify your question a little.</p> <p>Using more info I think you want something more like this:</p> <pre><code> private static int[,] FillArrays(string file, int rightLength) { int[] mArray = File.ReadAllLines(file).Select(x =&gt; int.Parse(x)).ToArray(); int size = mArray.Length / rightLength; if (((mArray.Length ^ rightLength) &gt;= 0) &amp;&amp; (mArray.Length % rightLength != 0)) { size++; } int[,] arrayDos = new int[size, rightLength]; int counter = 0; int arrayNum = 0; foreach (int i in mArray) { arrayDos[arrayNum, counter] = i; counter++; if (counter == rightLength) { counter = 0; arrayNum++; } } return arrayDos; } </code></pre> <p>And call it like this:</p> <pre><code>int[,] mArray = FillArrays(@"Z:\testnums.txt", 4); </code></pre> <p>You can pass in the right side size:</p> <pre><code>{int[8, 2]} [0, 0]: 0 [0, 1]: 1 [0, 2]: 2 [0, 3]: 3 [1, 0]: 0 [1, 1]: 1 [1, 2]: 2 [1, 3]: 3 [2, 0]: 0 [2, 1]: 2 [2, 2]: 2 [2, 3]: 3 [3, 0]: 0 [3, 1]: 1 [3, 2]: 3 [3, 3]: 3 </code></pre> <p>2 will also work with your example data.</p> <pre><code>{int[8, 2]} [0, 0]: 0 [0, 1]: 1 [1, 0]: 2 [1, 1]: 3 [2, 0]: 0 [2, 1]: 1 [3, 0]: 2 [3, 1]: 3 [4, 0]: 0 [4, 1]: 2 [5, 0]: 2 [5, 1]: 3 [6, 0]: 0 [6, 1]: 1 [7, 0]: 3 [7, 1]: 3 </code></pre>
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    1. POHow can i fill a multidimensional array from a text file?
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    1. CO`ReadAllLines` doesn't return an `int`...
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    2. CODoh! You are correct sir.
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    3. COand It has to be a int[,] mArray; , not a int[] mArray;
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      1. USEduardo Tenorio Mayo
 

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