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PO
primarykey
Id
20095486
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
3
CommunityOwnedDate
CreationDate
2013-11-20T12:04:23.363
FavoriteCount
0
LastActivityDate
2016-02-18T08:50:20.953
LastEditDate
2016-02-18T08:50:20.953
LastEditorUserId
1633814
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1633814
ParentId
6832596
PostTypeId
2
Score
8
ViewCount
0
LastEditorDisplayName
text
Body
Couldn't find a function doing what I wanted here. So I wrote my own. This is my contribution. I hope someone find it useful. Pros: <ul> <li>Handles version strings of arbitrary length. '1' or '1.1.1.1.1'.</li> <li>Defaults each value to 0 if not specified. Just because a string is longer doesn't mean it's a bigger version. ('1' should be the same as '1.0' and '1.0.0.0'.)</li> <li>Compare numbers not strings. ('3'<'21' should be true. Not false.)</li> <li>Don't waste time on useless compares in the loop. (Comparing for ==)</li> <li>You can choose your own comparator.</li> </ul> Cons: <ul> <li>It does not handle letters in the version string. (I don't know how that would even work?)</li> </ul> My code, similar to the accepted answer by Jon: <pre><code>function compareVersions(v1, comparator, v2) { "use strict"; var comparator = comparator == '=' ? '==' : comparator; if(['==','===','<','<=','>','>=','!=','!=='].indexOf(comparator) == -1) { throw new Error('Invalid comparator. ' + comparator); } var v1parts = v1.split('.'), v2parts = v2.split('.'); var maxLen = Math.max(v1parts.length, v2parts.length); var part1, part2; var cmp = 0; for(var i = 0; i < maxLen && !cmp; i++) { part1 = parseInt(v1parts[i], 10) || 0; part2 = parseInt(v2parts[i], 10) || 0; if(part1 < part2) cmp = 1; if(part1 > part2) cmp = -1; } return eval('0' + comparator + cmp); } </code></pre> Examples: <pre><code>compareVersions('1.2.0', '==', '1.2'); // true compareVersions('00001', '==', '1.0.0'); // true compareVersions('1.2.0', '<=', '1.2'); // true compareVersions('2.2.0', '<=', '1.2'); // false </code></pre>
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1. POHow to compare software version number using js? (only number)
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1. USViktor
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1. USViktor
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