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POMultiple Separators for the same file input R
 

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  1. POMultiple Separators for the same file input R
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    <p>I've had a look for answers, but have only found things referring to C or C#. I realise that much of R is written in C but my knowledge of it is non-existent. I am also relatively new to R. I am using the current Rstudio.</p> <p>This is similar to what I want, I think. <a href="https://stackoverflow.com/questions/17606321/read-the-data-efficiently-with-multiple-separating-lines-in-r">Read the data efficiently with multiple separating lines in R</a></p> <p>I have a csv file but one variable is a string with values separated by <code>_</code> and <code>-</code> And I would like to know if there is a package or extra code which does the following on the read. command.</p> <pre><code>"1","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",0,218,4,93,1377907200000 "2","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",0,390,5,157,1377993600000 "3","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",0,376,5,193,1.37808e+12 "4","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",1,35,1,15,1377907200000 "5","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",12,11258,117,2843,1377993600000 "6","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",5,4659,56,1826,1.37808e+12 "7","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_ANDROID","2013-08-31 13:39:55.0","2013-10-16 13:58:00.0",7,7296,136,2684,1377907200000 "8","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_IOS_IPAD","2013-08-31 13:18:21.0","2013-10-16 13:58:00.0",0,4533,35,1632,1377907200000 "9","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_IOS_IPAD","2013-08-31 13:18:21.0","2013-10-16 13:58:00.0",0,421,6,161,1377993600000 "10","Client1","Name2","*Name3_Name1_KB_MobApp_M-13-44_AU_PI Likes by KB_IOS_IPAD","2013-08-31 13:18:21.0","2013-10-16 13:58:00.0",0,57,2,23,1.37808e+12 </code></pre> <p>Example row:</p> <pre><code>Name Name1 *XYZ_Name3_KB_MobApp_M-18-25_AU_PI ANDROID 2013-09-32 14:39:55.0 2013-10-16 13:58:00.0 0 218 4 93 1377907200000 </code></pre> <p>So it's easy enough to read in </p> <pre><code>results &lt;- read.delim("~/results", header=F) </code></pre> <p>but then I still have the string *XYZ_Name3_KB_MobApp_M-18-25_AU_PI</p> <p>Desired output(separate by <code>_</code> and by <code>-</code>):</p> <pre><code>Name Name1 *XYZ Name3 KB MobApp M 18 25 AU PI ANDROID 2013-09-32 14:39:55.0 2013-10-16 13:58:00.0 0 218 4 93 1377907200000 </code></pre> <p>but not split up the time string.</p> <p>---- Thanks @Henrik and @AnandaMahto for the code and package. ----</p> <pre><code>library(splitstackshape) # split concatenated column by `_` df4 &lt;- concat.split(data = df3, split.col = "V3", sep = "_", drop = TRUE) # split the remaining concatenated part by `-` df5 &lt;- concat.split(data = df4, split.col = "V3_5", sep = "-", drop = TRUE) </code></pre>
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    1. COI have the option of exporting again to csv and then putting into excel and using text to columns twice. but as I'm on excel 2010 it's with a limited # of rows.
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    2. COHave a look at `str_split` or `stringr::str_split_fixed` and see if that helps.
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    3. COAh, so simple. Do you think I should do it it multiple steps then? Rather than on import.
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