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    <p>The difference is one, as you say, takes a typical int array <code>a[]</code>, but how would you know the size? So this version requires the user to send it to the function with <code>n</code> as the number of elements. In your <code>Array</code> class you provide a size so there's no need for it. In general you're providing overloads for multiple situations. </p> <p>I'm not sure what you mean by replacing <code>int a[]</code> w/ <code>&amp;arr</code>, the signature is there, use what was given to you unless you're <em>supposed</em> to change it.</p> <p>If you go back to your question about the <code>Array</code> class you can see an answer which uses the reference just as you would normally, i.e,</p> <pre><code>template &lt;class T&gt; Array&lt;T&gt;::Array(const Array &amp;other) : size(other.size), arr(new T[size]) { // ^^^^^^ for (int i = 0; i &lt; size; ++i) arr[i] = other.arr[i]; } // ^^^^^ </code></pre> <p>now apply it to this situation.</p> <p>Also,</p> <pre><code>template &lt;class T&gt; void selectionSort(Array&lt;T&gt; &amp;a) { // I'm not sure I understand what this is supposed to do that's different from the above selectionSort. // I know that &amp; is the reference operator, so should I just return whatever &amp;a is? } </code></pre> <p>You won't be returning anything here considering <code>void</code> as the return and the use of the reference. You pass by reference as opposed to by value so that what you do in the function is persistent. You <em>could</em> choose to pass back the sorted array and not use a reference but I'm fairly certain it'd be slower overall considering the assignment and copy. That's why the example from your other question is using <code>const Array &amp;other</code>. It prevents the entire array, which may be large, from being copied and sent to the function as well as being changed.</p>
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    1. POImplementing a sort class using templates
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    1. COSo, using the example from my `Array` class, would the code for `void selectionSort(Array<T> &a);` be similar, just with `a.whatever`?
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    2. COWell that depends. You can do `a.whatever` if `whatever` is `public`. If it's `private` you'd need to implement getters/setters.
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    3. CO@iKyriaki: the example is actually a little funny, IMHO, you have the `[]` operator overloaded so `other.arr[i]` should result in the same thing as `other[i]`, unless I'm missing something by skimming.
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