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    <p>The <code>%c</code> format string will always interpret the corresponding <code>printf</code> argument as a character. In this case, its probably not what you want.</p> <pre><code>printf("ASCII in BIN: %d\n", myChar); </code></pre> <p>will print out the ascii code point of <code>myChar</code> just by telling <code>printf</code> to treat it as a number.</p> <p>If you'd like to print out the string being returned by your <code>toBinary</code> function, you can do that with</p> <pre><code>printf("ASCII in BIN: %s\n", toBinary(myChar)); </code></pre> <p>There's a good reference of the various <code>%</code> codes and what they mean <a href="http://www.cplusplus.com/reference/cstdio/printf/" rel="nofollow">here</a>.</p> <hr> <p>However, it's also worth noting that your <code>toBinary</code> function probably doesn't do what you want. This loop condition:</p> <pre><code>for (int i = sizeof(binaryValue); i &gt;= 0; ++i) </code></pre> <p>will start at <code>sizeof(int)</code> and count up until it runs out of integers, then stop only because <code>INT_MAX + 1 == INT_MIN</code>. Because you're using <code>i</code> as an array index, this will almost certainly crash your program.</p> <p>You also need to make sure to terminate the string you're generating with a <code>'\0'</code>, as that is how subsequent calls to <code>printf</code> will recognize the string has ended.</p> <p>And, as noted in other answers, your <code>toBinary</code> implementation is also returning a pointer to a memory address that will get automatically deleted as soon as <code>toBinary</code> returns.</p>
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    1. POHow can I print the decimal representation of a character in c?
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    1. COThanks! I understand what I made wrong with the printf and the for loop. However, how can I fix my `toBinary` function?
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    2. COThe string its generating should be passed in as a parameter rather than returned. That would solve the immediate deletion issue. Also, since you want a binary representation, and sizeof works in bytes, you'll need to multiply by 8 to get the right number of bits. Other than that, and the stuff noted in my answer, your basic algorithm is fine.
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