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    <p>You have quite a few issues here, but generally you should be posting your data, not using a GET url, to create a post: domain.com/controller/action/some/data/here is a get request. domain.com/controller/action is your post URL, with the data in the post url form params. You would then bind your action to a model, and not to single params like you have done.</p> <p>Here is some code I use in my baseclass to make all API calls, when calling the API from serverside code:</p> <pre><code>public string CreateApiRequest(string url, object model, bool isPost) { try { ASCIIEncoding encoding = new ASCIIEncoding(); string postData = ""; if(model != null) { postData = Strings.SerializeToQueryString(model).TrimEnd(Convert.ToChar("&amp;")); } byte[] data = encoding.GetBytes(postData); var serviceUrl = "http://" + HttpContext.Request.Url.Host + "/api/{0}"; // create the post and get back our data stream var myRequest = (HttpWebRequest)WebRequest.Create(new Uri(string.Format(serviceUrl, url))); if (isPost) { myRequest.Method = "POST"; myRequest.ContentType = "application/x-www-form-urlencoded"; myRequest.Accept = "application/json"; myRequest.ContentLength = data.Length; Stream newStream = myRequest.GetRequestStream(); // Send the data. newStream.Write(data, 0, data.Length); newStream.Close(); } else { myRequest.Method = "GET"; myRequest.Accept = "application/json"; } // Get response using (HttpWebResponse response = myRequest.GetResponse() as HttpWebResponse) { // Get the response stream var reader = new StreamReader(response.GetResponseStream()); // Read the whole contents and return as a string var myString = reader.ReadToEnd(); return myString; } } catch (Exception ex) { // handle error here, I have my own custom mailer throw; } } </code></pre> <p>and this is how I call it.</p> <pre><code>var model = JsonConvert.DeserializeObject&lt;List&lt;Address&gt;&gt;(CreateApiRequest(url: "Address", model: null, isPost: false)); </code></pre> <p>hope this helps </p>
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