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PO
 

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  1. PO
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    <p>You should union both results and check rows for it like below :</p> <pre><code>select transaction_id, sum(order_id) as order_id, sum(payment_id) as payment_id from ( SELECT t.transaction_id, ROW_NUMBER() OVER (PARTITION BY t.transaction_id ORDER BY order_id) RowNo, o.order_id, null as payment_id FROM TRANSACTIONS t LEFT JOIN ORDERS o on o.transaction_id = t.transaction_id union SELECT t.transaction_id, ROW_NUMBER() OVER (PARTITION BY t.transaction_id ORDER BY payment_id) RowNo, null as order_id, p.payment_id FROM TRANSACTIONS t LEFT JOIN Payments p on p.transaction_id = t.transaction_id ) tt group by transaction_id, RowNo </code></pre> <p>SQL Fiddle Demo : <a href="http://sqlfiddle.com/#!3/e991d/21" rel="nofollow">http://sqlfiddle.com/#!3/e991d/21</a></p> <p><strong>UPDATE :</strong></p> <p>Please try it with JOIN instead of UNION like below :</p> <pre><code>SELECT t1.transaction_id, t1.order_id, t2.payment_id from ( SELECT t.transaction_id, ROW_NUMBER() OVER (PARTITION BY t.transaction_id ORDER BY order_id) RowNo, o.order_id FROM TRANSACTIONS t LEFT JOIN ORDERS o on o.transaction_id = t.transaction_id ) t1 full join ( SELECT t.transaction_id, ROW_NUMBER() OVER (PARTITION BY t.transaction_id ORDER BY p.payment_id) RowNo, p.payment_id FROM TRANSACTIONS t LEFT JOIN Payments p on p.transaction_id = t.transaction_id ) t2 on t1.transaction_id = t2.transaction_id and t1.RowNo = t2.RowNo </code></pre> <p>SQL Fiddle Demo : <a href="http://sqlfiddle.com/#!3/e991d/20" rel="nofollow">http://sqlfiddle.com/#!3/e991d/20</a></p>
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    1. POJoin two tables on one without mutyplying rows per record
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    1. USUpendra Chaudhari
    1. USUpendra Chaudhari
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    1. POJoin two tables on one without mutyplying rows per record
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    1. COSolution works but ``UNION`` makes it is very slow. Can you think of another way that would not force two passes? I'll vote up the answer because it does what it should.
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      1. USDusan Vasiljevic
    2. COPlease try with my updated answer using join
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      1. USUpendra Chaudhari
    3. COYou forgot to add ``partition by transaction_id``. This has almost the same cost as ``UNION``, but it is better. I'll mark this as an answer in a day if no one comes up with more optimized solution.
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