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    <p>Since you haven't actually tried any code, I'll give a description of how to solve this problem, but no actual code.</p> <p>Start with a <code>boolean</code> like <code>pairFound</code> that's initialized to <code>false</code> and change to <code>true</code> when you find your first <code>pair</code>. Additionally, you'll need an <code>int</code> (<code>pairValue</code> to keep track of the value of the first pair found (if you found one).</p> <p>Iterate through, looking for a pair. If you find a pair, and <code>pairFound</code> is false, set <code>pairFound</code> to <code>true</code>, and set <code>pairValue</code> to the value of your first found <code>pair</code>. Now keep iterating through.</p> <p>If you find a pair and <code>pairFound</code> is <code>true</code> and the pair is <code>!= pairValue</code>, then <code>return true;</code>. If you iterate through everything and haven't returned <code>true</code> yet, then you can <code>return false</code>.</p> <hr> <p>Based on your updated question, you're pretty close.</p> <pre><code>boolean pairFound = false; int pairValue = Integer.MIN_VALUE; //or some value that arrayOfInts will never have based on context for(int s = 0; s &lt; arrayOfInts.length - 1; s++){ if(arrayOfInts[s] == pairValue) { continue; } for(int c = s + 1; c &lt; arrayOfInts.length; c++){ if(arrayOfInts[s] == arrayOfInts[c]) { if(arrayOfInts[s] != pairValue) { if(pairFound) { return true; } pairValue = arrayOfInts[s]; pairFound = true; break; } } } } return false; </code></pre>
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    1. POHow to check if an array has two different pairs of matching values?
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    1. POHow to check if an array has two different pairs of matching values?
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    1. COI'll try that and let you know how it went!
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    2. CO_"Iterate through, looking for a pair"_ -- That's pretty vague, unless one assumes that the array is sorted.
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    3. CO@TedHopp I left my answer pretty intentionally vague. He put literally no effort into trying to solve this on his own, so I'm not going to put much effort into my answer. My question is a good explanation of how to go about tackling the problem. If he comes back with some specific problems/questions, he can get some more descriptive answers.
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