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POsubsetting in a specific sequence of time points in R, can I use seq?
 

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    <p>I have a data frame that looks like this:</p> <pre><code>structure(list(A = c(70, 70, 70, 70, 70, 70), T = c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6), X = c(434.01, 434.01, 434.75, 434.75, 434.75, 434.01), Y = c(454.92, 454.92, 454.92, 454.92, 454.18, 454.92 ), V = c(0, 0, 21.128, 0, 14.94, 14.94), thetarad = c(0.151841552716899, 0.151841552716899, 0.150990672182432, 0.150990672182432, 0.150177486839524, 0.151841552716899), thetadeg = c(8.69988012340509, 8.69988012340509, 8.6511282599214, 8.6511282599214, 8.6045361718215, 8.69988012340509 )), .Names = c("A", "T", "X", "Y", "V", "thetarad", "thetadeg" ), row.names = 1423:1428, class = "data.frame") </code></pre> <p>I want to subset specific time points in R with intervals of 30 sec. I can do this by manually subsetting each time point that I want:</p> <pre><code>a1=subset(binA, T==0.1) a2=subset(binA, T==30) a3=subset(binA, T==60) a4=subset(binA, T==90) a5=subset(binA, T==120) a6=subset(binA, T==150) a7=subset(binA, T==180) a8=subset(binA, T==210) a9=subset(binA, T==240) a10=subset(binA, T==270) a11=subset(binA, T==300) a12=subset(binA, T==330) a13=subset(binA, T==360) a14=subset(binA, T==390) a15=subset(binA, T==420) a16=subset(binA, T==450) a17=subset(binA, T==480) a18=subset(binA, T==510) a19=subset(binA, T==540) a20=subset(binA, T==570) a21=subset(binA, T==599.5) </code></pre> <p>I tried subsetting using <code>sapply</code>and the <code>seq</code> function but got confusing results. I also want to count the unique A in each subset of data. I also know I can do this using the <code>count</code> function in <code>plyr</code>package.</p> <pre><code>a1=count(unique(subset(binA, T==0.1))) </code></pre> <p>but count will work with one data frame and not multiple ones (correct me if I am wrong). I also want to take the means of thetadeg for each subset (this should be easy for sapply in one data frame only). So I need help on how to write a function with specific seq points.</p> <p>I know this problem is trivial but help would be appreciated.</p> <p>Thanks</p>
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    1. COPerhaps `cut` or `findInterval` would be of use here....
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