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    <p>Well, as much as I appreciate what you're doing, I find this easier to read:</p> <pre><code>int count = 0; int cards_amount = 52; for (var first = 0; first &lt; cards_amount-4; first++) for (var second = first + 1; second &lt; cards_amount-3; second++) for (var third = second+1; third &lt; cards_amount-2; third++) for (var fourth = third+1; fourth &lt; cards_amount-1; fourth++) for (var fifth = fourth+1; fifth &lt; cards_amount; fifth++) count++; </code></pre> <p>Instead of looking at all the duplicates, and the <code>if this card is different from the previous</code>, what I do is: Put all cards in a row. Select the first, and then the second from the remaining, and then the third from the remaining ... and so on.</p> <p>This way, you don't need to check for multiples, and you get your right answer :)</p> <p><strong>Edit:</strong><br> As for the comment ... Just add this line after you initialize your list: </p> <pre><code>var deck_array = deck.ToArray(); </code></pre> <p>You might want to do this on your <code>class card</code>:</p> <pre><code>public override string ToString() { // have this print your card number &amp; suit } </code></pre> <p>And then, just change the <code>count++;</code> line with this:</p> <pre><code>{ count ++; Console.WriteLine("{0},{1},{2},{3},{4}", deck_array[first], deck_array[second], deck_array[third] , deck_array[fourth] , deck_array[fifth] ); } </code></pre> <p>Solved ... (now your cards know how to print themselves, and you're just printing the hand at the end.</p>
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    1. COty for trying to help, but I need to make that my program write all possible hands, including numbers and suits of cards and in the end count of all possible combinations, somthing like I tried to make it in my code above...
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