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POurllib error: cannot fetch html data. Python, Beagle Bone Black
 

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    <p>I was making my project on mac and I tried to do the same things by Beagle Bone Black(BBB). However, I couldn't use urllib in BBB so I am stuck: I cannot go forward.(it is working well in my mac)</p> <p>I tried this simple code as an example: </p> <pre> import urllib conn = urllib.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content') </pre> <p>then this Error occurred:</p> <pre><code>Traceback (most recent call last): File "&lt;stdin&gt;", line 1, in &lt;module&gt; File "/usr/lib/python2.7/urllib.py", line 86, in urlopen return opener.open(url) File "/usr/lib/python2.7/urllib.py", line 207, in open return getattr(self, name)(url) File "/usr/lib/python2.7/urllib.py", line 351, in open_http 'got a bad status line', None) IOError: ('http protocol error', 0, 'got a bad status line', None) </code></pre> <p>I need to fetch a html data for my project. How can I solve this problem? Do you have any ideas ? Thank you.</p> <p>When I tried <code>urllib2</code> I got this:</p> <pre><code>&gt;&gt;&gt; import urllib2 &gt;&gt;&gt; conn = urllib2.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content') Traceback (most recent call last): File "&lt;stdin&gt;", line 1, in &lt;module&gt; File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "/usr/lib/python2.7/urllib2.py", line 400, in open response = self._open(req, data) File "/usr/lib/python2.7/urllib2.py", line 418, in _open '_open', req) File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain result = func(*args) File "/usr/lib/python2.7/urllib2.py", line 1207, in http_open return self.do_open(httplib.HTTPConnection, req) File "/usr/lib/python2.7/urllib2.py", line 1180, in do_open r = h.getresponse(buffering=True) File "/usr/lib/python2.7/httplib.py", line 1030, in getresponse response.begin() File "/usr/lib/python2.7/httplib.py", line 407, in begin version, status, reason = self._read_status() File "/usr/lib/python2.7/httplib.py", line 371, in _read_status raise BadStatusLine(line) httplib.BadStatusLine: '' </code></pre> <p>Also I tried this:</p> <pre><code>curl http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content curl: (52) Empty reply from server </code></pre> <p>and this:</p> <pre><code>wget http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content Connecting to stackoverflow.com (198.252.206.16:80) wget: error getting response </code></pre> <p>but they didn't work </p> <p>at home, I also tried and failed but returns a different error:</p> <pre><code>conn = urllib2.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content') Traceback (most recent call last): File "&lt;stdin&gt;", line 1, in &lt;module&gt; File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "/usr/lib/python2.7/urllib2.py", line 400, in open response = self._open(req, data) File "/usr/lib/python2.7/urllib2.py", line 418, in _open '_open', req) File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain result = func(*args) File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open return self.do_open(httplib.HTTPSConnection, req) File "/usr/lib/python2.7/urllib2.py", line 1177, in do_open raise URLError(err) urllib2.URLError: &lt;urlopen error [Errno -2] Name or service not known&gt; </code></pre> <p><strong>environment</strong></p> <pre><code>BBB: Linux beaglebone 3.8.13 #1 SMP Tue Jun 18 02:11:09 EDT 2013 armv7l GNU/Linux python version: 2.7.3 </code></pre>
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    1. COIs there a reason you're using the deprecated `urllib.urlopen` instead of `urllib2.urlopen`? I doubt that's your problem, but still, it's not a good idea to use deprecated functions unless you have a good rationale.
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    2. COMeanwhile, have you tried reading the same URL from the console with `curl` or `wget` to make sure it works? If so, you may need to go to a lower level in Python (either `httplib`, or just create a `socket` and send a hand-crafted result) and/or put a simple proxy in between to see what your code is doing wrong, what that status line is that it doesn't like, etc.
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    3. COyes you are right. I shouldn't use deprecated module. anyway,I got the error even when I used `urllib2`: I wrote the error above. I tried both `curl` and `wget` but I got an error
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