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POJavascript parse string to integer
 

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    <p>Working over at codewars I was trying to solve this problem:</p> <p>In this kata we want to convert a string into an integer. The strings simply represent the numbers in words.</p> <p>Examples:</p> <ul> <li>"one" => 1</li> <li>"twenty" => 20</li> <li>"two hundred forty-six" => 246</li> <li>"seven hundred eighty-three thousand nine hundred and nineteen" => 783919</li> </ul> <p>==================================================================================</p> <p>I came up with the code below to do this. <a href="http://jsfiddle.net/eaRGG/" rel="noreferrer">On jsfiddle for you convience.</a></p> <p><strong><em>A problem I've run into is 'seven hundred thousand' gives you 10700.</em></strong></p> <p>I've spent a day looking around and trying to figure this out but am just flat stuck. The steps the program takes is:</p> <ul> <li>string becomes 'thousand hundred seven' - good</li> <li>first while loop finds 'thousand' and sets multiplier to 1000 - good</li> <li>second while loop finds 'hundred' but then the mult.exec(a[0]) if statement resolves to null. - damn</li> </ul> <p>So instead of the multiplier becoming 100000, the value becomes 100000, and we are doomed to get the wrong answer.</p> <p>While trying to debug this I tried creating the a array being used during the second loop in the while in jsfiddle. There it worked and equated to 'hundred' instead of null. Anyone know why this would happen? </p> <pre><code>function parseInt(number) { // reference array for english -&gt; integer var ref = { one:1, two:2, three:3, four:4, five:5, six:6, seven:7, eight:8, nine:9, ten:10, eleven:11, twelve:12, thirteen:13, fourteen:14, fifteen:15, sixteen:16, seventeen:17, eighteen:18, nineteen:19, twenty:20, thirty: 30, forty: 40, fifty: 50, sixty: 60, seventy: 70, eighty: 80, ninety:90, hundred: 100, thousand: 1000, million: 1000000 }; // regex to find number values from the string var find = new RegExp( "(one|t(wo|hree|en|welve|hirteen|wenty|hirty)|f(our|ive|ourteen|iftenn|orty|ifty)|s(ixteen|ixty|eventy|ix|even|eventeen|teen)|eigh(ty|t|teen)|nin(ety|e|eteen)|zero|hundred|thousand|million)", "gi" ); // hundred/thousand/million etc. act as multipliers in this solution and need a seperate search var mult = new RegExp( "(hundred|thousand|million)", "gi" ); // reversing the string allows us to add largest digits first number = number.split(' ').reverse().join(" "); // while there is a number in string number // if that number is a multiplier // if that number is 100 -&gt; multiplier = multiplier * 100; // else multiplier = reference value; // else value = value + reference value * multiplier // end while value = 0; multiplier = 1; while( a = find.exec(number) ) { if( m = mult.exec(a[0]) ) { if( m[0] == 'hundred' ) { multiplier *= 100; } else { multiplier = ref[m[0]]; } } else { value += ref[a[0]] * multiplier; } } return value; } </code></pre>
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    1. COThat's an interesting problem you're working on, and I can't say that I fully understand your code. There are a few gotchas in there, though, that aren't directly related to your problem. 1) you may want to avoid a name collision with the built-in 'parseInt' function. It may not be impacting your codes behavior but that's probably a bad practice to use a built-in name like that.
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      1. USMike Edwards
    2. CO2) your `find` regular expression doesn't properly guard against matching proper prefixes - in your example JS fiddle it appears to match 'seven' as a proper prefix when it should match 'seventeen'. You'll want to include white space guards within the regular expression string to force full-word matching.
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    3. CONeat idea, I'm going to incorporate this in my French lexical analyzer to suggest number (int) representation in place of word (string) representation when numbers grow too large. Agreed with @MikeEdwards though - there are some cases that you may want to be aware of: `7` would be the result of `seven` and `seventeen` because the RegEx stops matching when it finds the first valid piece (`seven`). `4` in `four` and `fourteen` is also another example. You need a workaround, like the one he suggested. Also, isn't it interesting that every number in English can be broken down into 30 or so parts?
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      1. USChris Cirefice
 

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