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    <p><code>Uncaught SyntaxError: Unexpected string</code> is coming from <code>JSON.parse</code>, this is because it is no longer valid JSON (<a href="http://json.org/" rel="nofollow noreferrer">http://json.org/</a>)</p> <p>What you are doing is adding an object to an object, which turns out to be a string</p> <p><img src="https://i.stack.imgur.com/t0ZfE.png" alt="enter image description here"></p> <p>Then when you go to stringify it, the entire thing will be taken is just a string the first time and the second time. So it will go through fine, then the third time when it tries to parse it, the function will fail because you have added a JSON object with a string.</p> <p>If you are only storing JSON objects you can use jQuery's extend function (<a href="http://api.jquery.com/jQuery.extend/" rel="nofollow noreferrer">http://api.jquery.com/jQuery.extend/</a>)</p> <p>Or if you are storing more then just objects change it all to an array </p> <p>This should cover everything</p> <pre><code>function addtoStorage(key, data) { if (typeof(Storage) !== "undefined") { if (localStorage.getItem(key)) { console.log("Local Storage stuff" + localStorage.getItem(key)); var olddata = JSON.parse(localStorage.getItem(key)); var newdata = null; if(olddata instanceof Array){ olddata.push(data); newdata = olddata; }else if(data instanceof Array || !(data instanceof Object) || !(olddata instanceof Object)){ newdata = [olddata, data]; }else if(data instanceof Object &amp;&amp; olddata instanceof Object){ newdata = $.extend(olddata, data); } var dataJSON = JSON.stringify(newdata); localStorage.setItem(key, dataJSON); } else { var dataJSON = JSON.stringify(data); localStorage.setItem(key, dataJSON); } } else { console.log("You don't have storage capabilities. Sorry. Next time improve your browser."); } } </code></pre>
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    1. CO1) Thanks a lot. This answer works which is awesome. In terms of optimization however, this answer rewrites all the data to the localStorage every time. This seems like adding unnecessary operations to the dataStorage. Would there be anyway not to read and extend the entire storage value to increase efficiency?
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    2. COHopefully my question made sense.
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    3. CONah, sorry but the only way you can do this is reading then writing, if you really wanted to do optimizations to it you could keep one object in localStorage for the keys and the other for values, then you could create a map of keys for a single key, then when retrieving the value you could extend it there rather then reading and writing.
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Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

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