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POCalculate sum divisible by 3 using recursion
 

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  1. POCalculate sum divisible by 3 using recursion
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    <p>I need help in figuring out how to return the sum of all numbers in a 2d array entered from a keyboard which are divisible by three. I have my compute sum method that will return one test case correctly, however it does not calculate correctly for every case given. Any suggestions would be very helpful. I will load my code including the while loop to make it easier to find where I am calculating wrong.</p> <pre><code>try { InputStreamReader stream = new InputStreamReader (System.in); BufferedReader scan = new BufferedReader(stream); inputParser = Integer.parseInt(input); int i = 0; while(inputParser != 0) { input = scan.readLine(); inputParser = Integer.parseInt(input); if(inputParser == 0) { inputParser = 0; } else { numbers1[i] = inputParser; i++; } } sum = computeSumDivisibleBy3(numbers1,0,numbers1.length-1); System.out.println("The sum of the numbers divisible by 3 is " + sum); } catch(NumberFormatException exception) { System.out.println("Please enter integers only"); } </code></pre> <p>here is the method to calculate the sum divisible by 3</p> <p>//instead of this original method, I've implemented yours just below this and it returns correctly</p> <pre><code>public static int computeSumDivisibleBy3(int[] numbers, int startIndex, int endIndex){ if (startIndex == endIndex) return numbers[endIndex]; else{ int sum1 = computeSumDivisibleBy3(numbers, startIndex, endIndex-1); if (numbers[endIndex] % 3 == 0) return sum1 + numbers[endIndex]; else return sum1; } } //newly implemented code public static int computeSumDivisibleBy3(int[] numbers, int startIndex, int endIndex){ if (startIndex == numbers.length-1) return numbers[startIndex] % 3 == 0 ? numbers[startIndex] : 0; else{ return (numbers[startIndex] % 3 == 0 ? numbers[startIndex] : 0) + computeSumDivisibleBy3( numbers, ++startIndex, endIndex ); } } </code></pre>
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