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19861890
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2013-11-08T14:51:18.100
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2013-11-08T22:52:29.247
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You can do what you want with a proxy object: <pre><code>class source_of_B { class B &source; source_of_B(B &source): source(source) {} friend class A; friend class B; }; </code></pre> Because it has no public constructors, creation of such object is restricted to its friends. So you can add public constructor to B that accepts the proxy without compromising your requirement to create B's at controlled locations: <pre><code>class B { int x; B(int x): x(x) {} friend class A; public: B(const source_of_B &arg): x(arg.source.x) {} }; class A { B b; public: A(): b(5) {} source_of_B create_object() { return source_of_B(b); } }; int main() { A a; B b = a.create_object(); } </code></pre> but you can no longer use <code>auto b = a.create_object();</code> with this method. Edit If your compiler supports <a href="http://en.wikipedia.org/wiki/Return_value_optimization" rel="nofollow">return value optimization</a>, which it probably does, you can go without the proxy. Just change <code>create_object()</code> to return <code>B</code> directly: <pre><code> B create_object() { return b; } auto b2 = a.create_object(); </code></pre> The copy constructor will be called by <code>create_object()</code> itself. The only problem would be that some (older) compilers have restrictions on the complexity of the function. See the Wikipedia article for example. Working example is at <a href="http://ideone.com/w1jKAd" rel="nofollow">http://ideone.com/w1jKAd</a>.
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1. POHow to prevent making objects of B class in any other way than in A class
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