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POConnect to MySQL from information provided by a form using javascript
 

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  1. POConnect to MySQL from information provided by a form using javascript
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    <p>I'm stuck on this problem. I've been trying to use <code>http()</code> but doesn't seem to do anything.</p> <p>Here's the form (It calls <code>ajax_request</code> when I submit, this works fine):</p> <pre><code>&lt;form name='form-main'&gt; &lt;input id='host' type='text' placeholder='Host' /&gt; &lt;input id='user' type='text' placeholder='Username' /&gt; &lt;input id='db' type='text' placeholder='Database' /&gt; &lt;input id='pass' type='password' placeholder='Password' /&gt; &lt;/form&gt; </code></pre> <p>and here's <code>ajax_request</code> part:</p> <pre><code>function ajax_request() { var host = document.getElementById('host').value; var user = document.getElementyById('user').value; var db = document.getElementById('db').value; var pass = document.getElementById('pass').value; var submitTo = 'DB.php'; //alert(submitTo); http('POST', submitTo, ajax_response, 'Host='+host); } </code></pre> <p>Here's <code>ajax_response</code>:</p> <pre><code>function ajax_response(data) { document.getElementById('web').value = data; } </code></pre> <p>Finally, here's the PHP <code>DB.php</code> I'm trying to call:</p> <pre><code>&lt;?php $Host = $_POST['Host']; $User = $_POST['User']; $DB = $_POST['DB']; $Pass = $_POST['Pass']; $iDB = new mysqli($Host, $User, $DB, $Pass); if($iDB-&gt;connect_errno) echo "no"; else echo "yes"; ?&gt; </code></pre> <p>What I'm trying to achieve here is to get the response either "yes" or "no" from the PHP and have it output on <code>ajax_response</code></p>
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