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19820330
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2013-11-06T18:51:39.003
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2013-11-06T19:17:18.190
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2013-11-06T19:17:18.190
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19819480
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<h1>Using hash</h1> <p>Since ruby-1.9, <a href="http://www.igvita.com/2009/02/04/ruby-19-internals-ordered-hash/" rel="nofollow">hash keys order is guaranteed</a>. A simple solution here would be to take advantage of that, by putting your requests in a hash and storing their result accessing the hash element by its key :</p> <pre><code>requests = { foo: [ 'a', 1 ], bar: [ 'b', 5 ], foobar: [ 'c', 2 ] } requests.each do |name, config| Thread.new( name, config ) do |name, config| sleep config[1] requests[ name ] = config[0] end end sleep 6 requests.each do |name, result| puts "#{name} : #{result}" end </code></pre> <p>Produces :</p> <pre><code>foo : a bar : b foobar : c </code></pre> <p>Thus, to match your provided code :</p> <pre><code>stop, i, text, requests = false, 0, '', {} until stop i += 1 requests[ i ] = nil Thread.new( i ) do |key| r = RestClient.post 'http://example.com' requests[ i ] = r.to_str sleep 1 # after a treatment, the value of stop will set to true end end # you will have to join threads, here text = requests.values.join </code></pre> <h1>Using array</h1> <p>If the last example is good for you, you could even simplify that using an array. Array order is of course guaranteed too, and you can take advantage of ruby array dynamic size nature :</p> <pre><code>a = [] a[5] = 1 p a => [nil, nil, nil, nil, nil, 1] </code></pre> <p>So, previous example can be rewritten :</p> <pre><code>stop, i, text, requests = false, 0, '', [] until stop i += 1 Thread.new( i ) do |key| r = RestClient.post 'http://example.com' requests[ i ] = r.to_str sleep 1 # after a treatment, the value of stop will set to true end end # you will have to join threads, here text = requests.join </code></pre>
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1. POHow to made a http request in a thread an keep the call order?
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1. POHow to made a http request in a thread an keep the call order?
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1. COIt works. Thanks for the great anwser.
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