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    <p>Here is a solution using dictionaries I just whipped up:</p> <pre><code>def iter_recursive_common_elements(lists, max_depth=None): data = [{k:set(v) for k,v in lists.iteritems()}] # guarantee unique depth = 0 def get_common_elements(lists, base): d = {} for k, v in lists.iteritems(): merged = k.split(':') potential = set(base).difference(merged) for target in potential: d[':'.join(sorted(merged+[target]))] = v.intersection(base[target]) return d if d else None while True: ret = get_common_elements(data[depth], data[0]) if not ret: break data.append(ret) depth += 1 yield data[depth] if max_depth and depth &gt; max_depth: break </code></pre> <hr> <p>Using it is simple enough:</p> <pre><code>lists = {'a':[1,2,3,4,5], 'b':[6,7,8,9,10], 'c':[1,3,5,7,9], 'd':[2,4,6,8,10], 'e':[4,5,6,7,8]} for x in iter_recursive_common_elements(lists): print x &gt;&gt;&gt; {'d:e': set([8, 4, 6]), 'a:b': set([]), 'a:c': set([1, 3, 5]), 'a:d': set([2, 4]), 'a:e': set([4, 5]), 'b:e': set([8, 6, 7]), 'b:d': set([8, 10, 6]), 'b:c': set([9, 7]), 'c:d': set([]), 'c:e': set([5, 7])} {'a:b:d': set([]), 'a:b:e': set([]), 'a:b:c': set([]), 'a:c:e': set([5]), 'c:d:e': set([]), 'a:c:d': set([]), 'b:c:d': set([]), 'b:c:e': set([7]), 'b:d:e': set([8, 6]), 'a:d:e': set([4])} {'b:c:d:e': set([]), 'a:b:c:e': set([]), 'a:b:c:d': set([]), 'a:c:d:e': set([]), 'a:b:d:e': set([])} {'a:b:c:d:e': set([])} </code></pre> <hr> <p>Can also clean up the output to match more what you wanted:</p> <pre><code>for x in iter_recursive_common_elements(lists): for k, v in sorted(x.items()): if v: print '(%s) : %s' % (k.replace(':', ', '), list(v)) &gt;&gt;&gt; (a, c) : [1, 3, 5] (a, d) : [2, 4] (a, e) : [4, 5] (b, c) : [9, 7] (b, d) : [8, 10, 6] (b, e) : [8, 6, 7] (c, e) : [5, 7] (d, e) : [8, 4, 6] (a, c, e) : [5] (a, d, e) : [4] (b, c, e) : [7] (b, d, e) : [8, 6] </code></pre>
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