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2013-11-06T05:28:14.230
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I think you can fix this by passing the full path name into <code>printRootStructure</code>: <pre><code>import os def printRootStructure(dirname,indent=0): for i in range(indent): print " ", print os.path.basename(dirname) # changed if os.path.isdir(dirname): for files in os.listdir(dirname): printRootStructure(os.path.join(dirname,files),indent+1) # changed </code></pre> As it was in your original code, you were passing just the last part (this is called the "basename") of each file into <code>printRootStructure</code> when you made the recursive calls. <h3>Working directory and path names</h3> Any time you start up a program on a modern computer, your program runs in a fixed location in the filesystem (this is called the "current working directory"). If you invoke a program from the commane-line, the current working directory is simply the path where you invoked the program's name. If you invoke a program by clicking something in a GUI environment, it can get more complicated, but the general behavior is the same: your program always runs in a specific working directory. All path tests, and in particular <a href="http://docs.python.org/2/library/os.path.html" rel="nofollow"><code>os.path.isdir</code></a>, are evaluated with respect to that working directory. So when you make your first recursive call in your example, you are testing <code>os.path.isdir("test1")</code>, which doesn't exist in the working directory -- it only exists inside "test" ! The fix is to pass the full path name into your recursive calls. Then, because your full name might be excessive when you print out the tree, I added a call to <a href="http://docs.python.org/2/library/os.path.html" rel="nofollow"><code>os.path.basename</code></a> to print just the basename portion of each file.
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