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    <pre><code>from numpy import * eps = 0.1 #ASSUMING the second arrow is sorted (otherwise sort it first) a= array( [[1, 1.2, 3], [2, 2.2, 3], [3, 2.25, 1], [4, 2.28, 4], [5, 3.2, 8], [6, 4.2, 10], [7, 4.21, 3], [8, 4.25, 4], [9, 4.28, 1], [10, 5.2, 10], ]) # expected result # a= [[1, 1.2, 3], # [3, 2.25, 1], # [5, 3.2, 8], # [9, 4.28, 1], # [10, 5.2, 10], # ] n = shape(a)[0] b = a[:,1] a1 = a[ (diff(b)&lt;eps) ] #indexes of some False that could be True. #these indexes should be checked backwards #and evtl. added to a1 indexes = where((diff(b)&lt;eps)==False)[0][1:] for index in indexes: if b[index] - b[index-1]&lt;eps: a1 = vstack( (a1,a[index,:]) ) #sort array a1 = a1[lexsort( (a1[:,1],a1[:,1]))] groups = where(diff(a1[:,1])&gt;eps)[0] i = 0 # get min of groups for g in groups: ag = a1[i:g+1,2] Ag = a1[i:g+1,:] if i == 0: a2 = Ag [ ag == min(ag) ] else: a2 = vstack( (a2, Ag [ ag == min(ag) ] ) ) i = g+1 #add last group ag = a1[g+1:,2] Ag = a1[g+1:,:] a2 = vstack( (a2, Ag [ ag == min(ag) ]) ) #the elements that build no groups result = a[ in1d(a[:,0], [ int(i) for i in a[:,0] if i not in a1[:,0] ]) ] # add the elements of a2, these are the minimal elements of each group result = vstack( (result, a2) ) # sort the result (optional) result = result[lexsort( (result[:,0], result[:,0]))] print "final result\n", result </code></pre> <p>Here is the output of this code</p> <pre><code>In [1]: run filter.py final result [[ 1. 1.2 3. ] [ 3. 2.25 1. ] [ 5. 3.2 8. ] [ 9. 4.28 1. ] [ 10. 5.2 10. ]] </code></pre>
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