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POMySQL WHERE IN returning one row
 

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    <p>So I've got what I think is a pretty simple SELECT query. The query itself looks like this:</p> <pre><code>"SELECT id FROM files WHERE name IN ("me_me-about.jpg", "me_me-blog.jpg", "me_me-.jpg") </code></pre> <p>Where I want the ids of those three files in my database. They're in their table. They have unique IDs. (I'm doing this so I can get the ids to insert into a junction table to associate them with user profiles, in case you're wondering.) I created the statement out of a $filenames array, that's just a simple, one-dimensional array of filenames:</p> <pre><code>$stmt = '('; for ($i = 0; $i &lt; sizeof($filenames); $i++) { $stmt .= '"' . $filenames[$i] . '", '; } $stmt = substr($stmt, 0, -2); $stmt .= ')'; $query2 = $this-&gt;db-&gt;prepare("SELECT id FROM files WHERE name IN " . $stmt); </code></pre> <p>Query returns one row, the last one. From everything I've seen of the WHERE... IN syntax, that shouldn't be? Is something haywire that I just can't see?</p> <p>CSV table dump of "files" from PMA (id, name, year [I'm coming back to that once this is working]):</p> <pre><code>"20";"me_me-about.jpg";;"0" "21";"me_me-blog.jpg";;"0" "22";"me_me-.jpg";;"0" </code></pre> <p>print_r of $filenames:</p> <pre><code>Array ( [0] =&gt; me_me-about.jpg [1] =&gt; me_me-blog.jpg [2] =&gt; me_me-.jpg ) </code></pre> <p>print_r of $stmt in its original form (with my code above):</p> <pre><code>("me_me-about.jpg", "me_me-blog.jpg", "me_me-.jpg") </code></pre> <p>Try-catch to execute. Output the $rows to $_SESSION so I can print_r it on the relevant page:</p> <pre><code>try { $query2-&gt;execute(); $rows = $query2-&gt;fetch(); $_SESSION['stmt'] = $rows; } catch (PDOException $e) { die($e-&gt;getMessage()); } </code></pre> <p>print_r of $_SESSION['stmt']:</p> <pre><code>Array ( [id] =&gt; 22 [0] =&gt; 22 ) </code></pre>
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    1. COAlso, what do you get when you run the **exact** same query in phpmyadmin or in the mysql console?
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      1. USMosty Mostacho
    2. COIn PMA I get all three rows. Which that's the weird thing.
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      1. USJeff
    3. COThen the error must be AFTER this code you've added here. How are you displaying the output? I bet the error is right there
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      1. USMosty Mostacho
 

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