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2013-10-29T23:24:33.447
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If you want to use your original code, you have to pass the filename to the <code>finder()</code> function, and open the file there, for each char you are testing for. The reason for this is that the file object (<code>in_file</code>) is a generator, not a list. The way a generator works, is that it returns the next item each time you call their <code>next()</code> method. When you say <pre><code>for line in in_file: </code></pre> The <code>for ... in</code> statement calls <code>in_file.next()</code> as long as the <code>next()</code> method "returns" (it actually use the keyword <code>yield</code>, but don't think about that for now) a value. When the generator doesn't return any values any longer, we say that the generator is exhausted. You can't re-use an exhausted generator. If you want to start over again, you have to make a new generator. I allowed myself to rewrite your code. This should give you the desired result. If anything is unclear, please ask! <pre><code>def finder_character(file_name,character): with open(file_name, "r") as ifile: if character=='vowel': brain_rat='aeiou' elif character=='consonant': brain_rat='bcdfghjklmnpqrstvwxyz' elif character=='space': brain_rat=' ' else: brain_rat='!@#$%^&*()_+=-123456789{}|":?><,./;[]\'' return sum(1 if c.lower() in brain_rat else 0 for c in ifile.read()) </code></pre> test.txt: <pre><code>eeehhh iii!# kk ="k oo o </code></pre> Output: <pre><code>>>>print(finder_character('test.txt', 'vowel')) 9 >>>print(finder_character('test.txt', 'consonant')) 6 >>>print(finder_character('test.txt', 'space')) 2 >>>print(finder_character('test.txt', '')) 4 </code></pre> If you are having problems understanding the <code>return</code> line, it should be read backwards, like this: <pre><code>Sum this generator: Make a generator with values as v in: for row in ifile.read(): if c.lower() in brain_rat: v = 1 else: v = 0 </code></pre> If you want to know more about generators, I recommend the <a href="https://wiki.python.org/moin/Generators" rel="nofollow">Python Wiki page</a> concerning it.
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