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    <p>You can use <code>int</code> to make this a lot easier. Function:</p> <pre><code>def hex_to_dex(strng_of_hex): return int(strng_of_hex, 16) </code></pre> <p>Example:</p> <pre><code>&gt;&gt;&gt; int("0xff", 16) 255 </code></pre> <p>It does not matter if you have a <code>0x</code> infront for int, it will ignore <code>0x</code> in the string. So, the following will also work:</p> <pre><code>&gt;&gt;&gt; int("a", 16) 10 </code></pre> <p>As for a raw hex code from scratch, try the following:</p> <pre><code>def hex(s): _hexer = "0123456789ABCDEF" return sum([_hexer.find(var) * 16 ** i for i, var in enumerate(reversed(s.upper()))]) </code></pre> <p>If you wanted to put some guards in:</p> <pre><code>def hex(s): _hexer = "0123456789ABCDEF" if not all([var in _hexer for var in s.upper()]): print "Invalid string" return None return sum([_hexer.find(var) * 16 ** i for i, var in enumerate(reversed(s.upper()))]) </code></pre> <p>I've used a lot of functions here, but for quick reference, here's an appendix:</p> <ol> <li><a href="http://docs.python.org/2/library/stdtypes.html#str.find" rel="nofollow">str.find</a></li> <li><a href="http://docs.python.org/2/whatsnew/2.3.html#pep-279-enumerate" rel="nofollow">enumerate</a></li> <li><a href="http://docs.python.org/2/library/functions.html#reversed" rel="nofollow">reversed</a> -> reverses the string</li> <li><a href="http://docs.python.org/2/library/functions.html#sum" rel="nofollow">sum</a></li> </ol> <p>As for the <code>[...]</code>, its a list comprehension, you can find loads of resources on that.</p>
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    1. COUnfortunately I have to write my own function to do this. I am going to do it by taking the length of the input string, and multiplying the first number by 16 to the power of length minus 1.
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    2. CO@JaAnTr Tr the latest addition.
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    3. CO`sum()` is the wrong function here. The `_hexer.find()` trick is cute, but the resulting value will be very wrong.
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      1. USMartijn Pieters
 

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