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19591511
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2013-10-25T13:41:27.743
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2013-10-25T13:41:27.743
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text
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I think there is a relatively simple solution to this, the algorithm is as follows: <pre><code>import java.util.Calendar; public class test { public static void main(String[] args){ Calendar today = Calendar.getInstance(); Calendar problemDate = Calendar.getInstance(); today.set(2013, 01, 05); problemDate.set(2012, 11, 05); System.out.println(today.getTime()); System.out.println(problemDate.getTime()); // This might need further validation to make sure today >= problemDate int diffYear = today.get(Calendar.YEAR) - problemDate.get(Calendar.YEAR); int differenceInMonths = diffYear * 12 + today.get(Calendar.MONTH) - problemDate.get(Calendar.MONTH); //int differenceInMonths = today.get(Calendar.MONTH) - problemDate.get(Calendar.MONTH); for(int i = 0; i <= differenceInMonths; i++) { int daysDifference; if (differenceInMonths == 0) { daysDifference = today.get(Calendar.DAY_OF_MONTH) - problemDate.get(Calendar.DAY_OF_MONTH); } else { if ( i == 0) { // first month daysDifference = problemDate.getActualMaximum(Calendar.DAY_OF_MONTH) - problemDate.get(Calendar.DAY_OF_MONTH); } else if( i == differenceInMonths ) { // last month daysDifference = today.get(Calendar.DAY_OF_MONTH); } else { Calendar cal= Calendar.getInstance(); cal.set(Calendar.MONTH, problemDate.get(Calendar.MONTH) + i); daysDifference = cal.getActualMaximum(Calendar.DAY_OF_MONTH); } } System.out.println(daysDifference); } } } </code></pre> Which outputs: <pre><code>Tue Feb 05 14:35:43 GMT 2013 Wed Dec 05 14:35:43 GMT 2012 26 31 5 </code></pre> You should be able to wrap this up into your code, and in a loop fairly easily, and also remove the print statements to insert into whatever data structure you have.
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1. POfind days difference between 2 dates and how many days in each month
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1. USHusman
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1. POfind days difference between 2 dates and how many days in each month
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