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POOrder a sentence alphabetically and count the number of times each words appears and print in a table
 

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    <p>I am struggling with the print in a table part of the question. So far I have managed to order the user inputted sentence alphabetically and count the number of times each word occurs. Here is the code:</p> <pre><code>thestring = (raw_input()) sentence = thestring.split(" ") sentence.sort() count = {} for word in thestring.split(): try: count[word] += 1 except KeyError: count[word] = 1 print sentence print count </code></pre> <p>And when I run the code I get this:</p> <pre><code>['apple', 'apple', 'banana', 'mango', 'orange', 'pear', 'pear', 'strawberry'] {'apple': 2, 'pear': 2, 'strawberry': 1, 'mango': 1, 'orange': 1, 'banana': 1} </code></pre> <p>However, ideally I want it printed in a table that looks something like:</p> <pre><code>apple.....|.....2 banana....|.....1 mango.....|.....1 orange....|.....1 pear......|.....2 strawberry|.....1 </code></pre> <p>Thanks for any help!</p>
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