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POfind days difference between 2 dates and how many days in each month
 

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  1. POfind days difference between 2 dates and how many days in each month
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    <p>I could use some help with this method I'm trying to make. I have a Problem Object, which has a target date and i need to find out how many days this problem is late divided/split by months, compared to today's date.</p> <p>Image this situation: Lets say that today's date is <strong>05-02-2013</strong>.</p> <pre><code>ID Target date P1 02-02-2013 P2 27-01-2013 P3 26-01-2013 P4 05-12-2012 </code></pre> <p>This means that each problem is this many days late in the following months:</p> <pre><code> DEC JAN FEB P1 3 P2 4 5 P3 5 5 P4 26 31 5 </code></pre> <p>A problem can not be older than 12 months.</p> <p>Now i need a method to sum these numbers storing the month name and a summed number of late days. If the target month and now month are the same, its an easy case, because i can just substract the days and store the month, but what to do when its not the case? I have the following code:</p> <pre><code>List&lt;Problem&gt; problems = problemQuery.getResultList(); //Problems list is already filtered and contain only late problems. Calendar now = Calendar.getInstance(); Calendar before = Calendar.getInstance(); Map&lt;Integer, Integer&gt; newMap = new TreeMap&lt;Integer, Integer&gt;(); //map that contains month number and daysLateCount for (Problem p : problems) { before.setTime(p.getTarget_date()); int nowMonth = now.get(Calendar.MONTH); int beforeMonth = before.get(Calendar.MONTH); if (beforeMonth == nowMonth) { //easy case when both dates have same month int result = now.get(Calendar.DAY_OF_MONTH) - before.get(Calendar.DAY_OF_MONTH); if (newMap.containsKey(nowMonth)) { int newLateDaysValue = newMap.get(nowMonth)+result; //get old result and add the new newMap.put(nowMonth, newLateDaysValue); } else { newMap.put(nowMonth, result); } } else { //What to do here??? } } </code></pre> <p>Perhaps i could even skip the if-else clause and make an algorithm that could handle both cases? I don't know please help :)</p>
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    1. USEmil Kaminski
    1. USEmil Kaminski
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    1. COIs there any possibility of a Problem being more than 12 months late? Specifically, could the late months include two or more Januarys, two or more Februarys, etc.?
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    2. COI should have included that in my question :). No the problem cant be older than 12 months
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      1. USEmil Kaminski
 

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