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    <p>No, you can't really; not the way you're creating objects at least.</p> <p>You can sort of do this, by enumerating all the functions on the object and binding them to the object itself. Something like this:</p> <pre><code>Object.keys(obj) .filter(function(n) { return typeof obj[n] == "function" }) .forEach(function(n) { obj[n] = obj[n].bind(obj) }) </code></pre> <p>This function will go over the public, enumerable properties of <code>obj</code> and make sure that any functions on it are bound to <code>obj</code>; i.e. <code>this</code> is now bound to <code>obj</code>.</p> <hr> <h2>A primer on <code>this</code></h2> <p>When you call new, <code>this</code> within the constructor gets bound to the newly created object. If you do need a reference to <code>this</code> as it was bound at constructor time, you do need to keep away a reference to it.</p> <p>Functions in JavaScript are bound to wherever it is called. Here's an example:</p> <pre><code>var foo = new function() { this.bar = function() { return 'bar' } this.baz = function() { return this.bar() } } console.log(foo.bar()) // bar console.log(foo.baz()) // bar var bar = function() { return "window" } var baz = foo.baz console.log(baz()) // window </code></pre> <p>When we call <code>foo.baz()</code> it'll look to <code>foo</code> for the implementation of <code>bar</code>, but when calling <code>foo.baz</code> through a "detached" reference, it'll look to whatever the global object is (in this case the browser window object) and call <code>bar</code> from there. Because we defined <code>bar</code> in the global context, it then returns <code>window</code>.</p> <p>The practice of assign a variable called <code>self</code> is so that it doesn't matter how you call your methods, because you always reference the <code>this</code> at the time of creation through the <code>self</code> variable. You don't have to write things this way, but then you should understand that references to <code>this</code> may change under your feet.</p>
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    1. POHow to set var self = this; from outside the function?
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    1. USMarcus Stade
    1. USMarcus Stade
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    1. POHow to set var self = this; from outside the function?
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    1. COThanks for clearing up why I was getting that result when trying to assign `self` in the last example!
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      1. USJared
    2. CODoes it answer your question?
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    3. COIt explains why I was getting the result that I'm currently getting, not how I can programmatically set `self` when instantiating my fake class. Or you could actually have answered it and I'm just getting caught up in the massing number of comments and answers. :s
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