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    <p>The best tool for the job here is recursion, not regular expressions. The basic idea is to start from the beginning of the string looking for a word, then take the remainder of the string and look for another word, and so on until the end of the string is reached. A recursive solution is natural since backtracking needs to happen when a given remainder of the string cannot be broken into a set of words. The solution below uses a dictionary to determine what is a word and prints out solutions as it finds them (some strings can be broken out into multiple possible sets of words, for example wickedweather could be parsed as "wicked we at her"). If you just want one set of words you will need to determine the rules for selecting the best set, perhaps by selecting the solution with fewest number of words or by setting a minimum word length.</p> <pre><code>#!/usr/bin/perl use strict; my $WORD_FILE = '/usr/share/dict/words'; #Change as needed my %words; # Hash of words in dictionary # Open dictionary, load words into hash open(WORDS, $WORD_FILE) or die "Failed to open dictionary: $!\n"; while (&lt;WORDS&gt;) { chomp; $words{lc($_)} = 1; } close(WORDS); # Read one line at a time from stdin, break into words while (&lt;&gt;) { chomp; my @words; find_words(lc($_)); } sub find_words { # Print every way $string can be parsed into whole words my $string = shift; my @words = @_; my $length = length $string; foreach my $i ( 1 .. $length ) { my $word = substr $string, 0, $i; my $remainder = substr $string, $i, $length - $i; # Some dictionaries contain each letter as a word next if ($i == 1 &amp;&amp; ($word ne "a" &amp;&amp; $word ne "i")); if (defined($words{$word})) { push @words, $word; if ($remainder eq "") { print join(' ', @words), "\n"; return; } else { find_words($remainder, @words); } pop @words; } } return; } </code></pre>
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    1. POHow can I split multiple joined words?
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    1. USRobert Gamble
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      1. VTUpMod
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    1. COhaven't run it, but it reads like a better solution than BKB's since it produces all possibilities.
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      1. USSquareCog
 

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