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POHow to increment counters based on a printed array
 

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  1. POHow to increment counters based on a printed array
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    <p>I managed to developed a simple board of 5x5 using random numbers and array. Big achievement for someone like me! :)</p> <p>Now I have to increment the counters depending on the frequency of the numbers.</p> <p>If the value within 0-49 is printed..then nCounter++ If the value within 50-75 is printed..then pCounter++ something like that.</p> <p>The problem is that I don't know how to <strong>increase the counters based on the printed board</strong>.</p> <p>Here is the code:</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;stdlib.h&gt; #include &lt;time.h&gt; int main() { //Initialize Variables int randomNumber; int rows; int columns; int hdCounter =0; int hCounter = 0; int cCounter = 0; int pCounter = 0; int nCounter = 0; //Declare board size int board[5][5]; //size of board is 5 x 5 //Create the random number generator seed srand(time(NULL)); //Assign the random numbers from 1 - 25 into variable randomNumber //Create the rows for the board for ( rows = 1; rows &lt;= 5 ; rows++ ) { //Create the colimns for the board for ( columns = 1; columns &lt;= 5 ; columns++ ) { //Assign variable randomNumber into variable board randomNumber = rand() %100 + 1; board[rows][columns] = randomNumber; //print the board printf("%d\t", board[rows][columns]); //calculate the frequency of numbers on the printed board if (randomNumber &gt;= 85 &amp;&amp; randomNumber &lt;= 100 ) hdCounter++; else if ( randomNumber &gt;= 75 ) hCounter++; else if ( randomNumber &gt;= 65 ) cCounter++; else if ( randomNumber &gt;= 50 ) pCounter++; else if ( randomNumber &gt;= 1 ) nCounter++; else continue; } //Newline after the end of 5th column. printf("\n\n"); } printf( "N \t P \t C \t H \t HD\n\n" ); printf("%d \t %d \t %d \t %d \t %d \t", nCounter, pCounter, cCounter, hCounter, hdCounter); }//end main </code></pre> <p>I tried replacing <code>randomNumber</code> in the if-statement with <code>board[rows][columns]</code> but I seem to get the same undesired results.</p>
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