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    <blockquote> <p>does the tree object use the methods within the Oak or Pine object?</p> </blockquote> <p>Yes. For instance, if <code>getbranch</code> is overridden in <code>Oak</code> or <code>Pine</code>, the version on the object being iterated, not the <code>wood</code> version, is called. So when you're looking at an <code>Oak</code>, <code>Oak</code>'s version is called; when you're looking at a <code>Pine</code>, <code>Pine</code>'s version is called. This is called <a href="http://en.wikipedia.org/wiki/Dynamic_binding_%28computing%29" rel="nofollow"><em>dynamic binding</em></a>, and it's the only kind of binding Java has. (Some languages, like C++, have both dynamic and static binding depending on how you declare the method; in Java, the closest you can come is the <code>final</code> keyword, which prevents you from overriding the method at all [and therefore would allow static binding in a compiler where that was relevant, such as the optimizations that the HotSpot Just-In-Time compiler can do].)</p> <hr> <p>Side notes:</p> <ol> <li><p>The overwhelming convention in Java is that class names are capitalized. Even more important is consistency. So if you have <code>Oak</code> and <code>Pine</code> classes, their base class should be <code>Wood</code>, not <code>wood</code>.</p></li> <li><p>Similarly, camelCase is used for methods (so, <code>getBranch</code>, not <code>getbranch</code>).</p></li> </ol> <p>Again, this is convention, which you can choose to ignore, but when communicating with others (for instance, here on SO!), following convention is useful.</p>
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    1. UST.J. Crowder
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    1. COHey, Mr. Crowder, won't there be a variable name collision as the OP has an `Oak tree` and then the variable in the for loop is also a local variable `tree` ?
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      1. USLittle Child
    2. CO@LittleChild: Yes and no. The quoted `for` loop is invalid, because the [enhanced `for` statement](http://docs.oracle.com/javase/specs/jls/se7/html/jls-14.html#jls-14.14.2) **requires** that you declare a new, loop-scoped variable. The quoted code doesn't have a type in front of it, and so won't compile. If it *did* compile, the `tree` within the loop would be the one declared in the loop, shadowing (hiding) the `tree` declared outside the loop.
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    3. COI actually do not understand what the OP wants to achieve. Maybe you can help me improve my answer ? :-)
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