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POhow to store the userid in the session variable for newly created user after registration
 

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  1. POhow to store the userid in the session variable for newly created user after registration
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    <p>I have a problem in fetching the value from the <code>userid</code> column of MySql table and storing it in session.</p> <p>Here is the problem in detail:</p> <p>I have a database with many tables but lets consider 2 for now.</p> <p>Table name <b>login</b>:<br></p> <pre><code>| userid | username | password </code></pre> <p>Table name <b>person_details</b>:</p> <pre><code>| firstname | lastname | dob </code></pre> <p>Other than this i have (consider) 2 pages with 2 forms (1 at each page);</p> <p>One for login and other for details after login.</p> <p>My <code>person_details</code> table's <code>userid</code> is foreign key to <code>login</code> table. </p> <p>what i want is when an user register, the provided <code>username</code> and <code>password</code> should be saved in the <code>login</code> table with an unique(autogenerated) <code>userid</code> which is currently working fine.*</p> <p>Now the problem is in this part; when the user is registered then he/she is directed to <code>person_details</code> form and on clicking submit after filling out the form, the data should save to <code>person_details</code> table <strong>with the same 'userid' as in 'login' table</strong>.</p> <pre><code>In order to do that I think i have to store the 'userid' in the session variable so that it can be used as a parameter while inserting the value to 'person_details' table but i am not able to pass that value. </code></pre> <p>here is my code:</p> <pre><code>if ((isset($_POST["MM_insert"])) &amp;&amp; ($_POST["MM_insert"] == "login")) { $insertSQL = sprintf("INSERT INTO secure_login (username, password) VALUES (%s, %s)", GetSQLValueString($_POST['username'], "text"), GetSQLValueString($_POST['password'], "text")); mysql_select_db($database_mydatabase, $mydatabase); $Result1 = mysql_query($insertSQL, $mydatabase) or die(mysql_error()); $obj = @mysql_fetch_object($Result1); $_SESSION['userID']=$obj-&gt;userid; </code></pre> <p>i tried this too but no luck</p> <pre><code> mysql_select_db($database_mydatabase, $mydatabase); $Result1 = mysql_query($insertSQL, $mydatabase) or die(mysql_error()); $_SESSION['userID']=$Result1-&gt;userid; </code></pre> <p>This is the error i am getting when trying:</p> <pre><code>Cannot add or update a child row: a foreign key constraint fails (`mydatabase`.`personaldetails`, CONSTRAINT `personaldetails_ibfk_2` FOREIGN KEY (`userid`) REFERENCES `secure_login` (`userid`) ON DELETE CASCADE ON UPDATE CASCADE) </code></pre> <p>and i tried it without session and it was ok, data was saved to the table <code>person_details</code> with autogenerated <code>userid</code>.</p> <p>Please let me know if u need anymore of the code or any other information.</p> <p><strong>EDIT</strong> I got the userID in session variable, so half of my problem is solved. Now all i need to do is to set the same userid for person_details.</p> <p>P.S. When i posted this question here, i expected an answer but all i got was some visits and a fellow doing some editing for me (which i think he enjoyed so much that he edited some of my comments as code) anyways, thank you friend.</p>
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