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POpython simple money code beginner
 

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  1. POpython simple money code beginner
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    <p>I'm doing suppose to convert a money value into a string value. Example: 10675.78 would turn to "ten thousand six hundred seventy five and 78/100 dollars</p> <p>I think I'm making this much more complicated than it needs to be. any suggestions?</p> <pre><code>def money(value): x = str(value) if len(x)&gt;8: return ("Error. Value exceeds limit.") elif len(x)==0: return ("Error. Must enter a value.") for len(x) in range(0,7): for x[6:8]: a = x[6:8] print(a,'/100 dollars') for x[3:5]: b = x[4:6] if b = '10' tens = 'ten' elif b = '11' tens = 'eleven' elif b = '12' tens = 'twelve' elif b = '13' tens = 'thirteen' elif b = '14' tens = 'fourteen' elif b = '15' tens = 'fifteen' elif b = '16' tens = 'sixteen' elif b = '17' tens = 'seventeen' elif b = '18' tens = 'eighteen' elif b = '19' tens = 'nineteen' else: return false for x[4]: c = x[4] if b = true: fifth = '' elif c = '9' fifth = 'nine' elif c = '8' fifth = 'eight' elif c = '7' fifth = 'seven' elif c = '6' fifth = 'six' elif c = '5' fifth = 'five' elif c = '4' fifth = 'four' elif c = '3' fifth = 'three' elif c = '2' fifth = 'two' elif c = '1' fifth = 'one' elif c = '0' fifth = '' for x[3]: d = x[3] if b = true: fourth = '' elif d = '9' fourth = "ninety " elif d = '8' fourth = "eighty " elif d = '7' fourth = "seventy " elif d = '6' fourth = "sixty " elif d = '5' fourth = "fifty " elif d = '4' fourth = "forty " elif d = '3' fourth = "thirty " elif d = '2' fourth = "twenty " elif d = '0' fourth = '' for x[2]: e = x[2] if e = '9' third = 'nine hundred ' elif e = '8' third = 'eight hundred ' elif e = '7' third = 'seven hundred ' elif e = '6' third = 'six hundred ' elif e = '5' third = 'five hundred ' elif e = '4' third = 'four hundred ' elif e = '3' third = 'three hundred ' elif e = '2' third = 'two hundred ' elif e = '1' third = 'one hundred ' for x[0:2]: j = [0:2] if j = '10' second = 'ten thousand ' elif j = '11' second = 'eleven thousand ' elif j = '12' second = 'twelve thousand ' elif j = '13' second = 'thirteen thousand ' elif j = '14' second = 'fourteen thousand ' elif j = '15' second = 'fifteen thousand ' elif j = '16' second = 'sixteen thousand ' elif j = '17' second = 'seventeen thousand ' elif j = '18' second = 'eighteen thousand ' elif j = '19' second = 'nineteen thousand' else: return false for x[1]: g = x[1] if j = true: second = '' elif g = '9' second = 'nine thousand ' elif g = '8' second = 'eight thousand ' elif g = '7' second = 'seven thousand ' elif g = '6' second = 'six thousand ' elif g = '5' second = 'five thousand ' elif g = '4' second = 'four thousand ' elif g = '3' second = 'three thousand ' elif g = '2' second = 'two thousand ' elif g = '1' second = 'one thousand' elif g = '0' second = '' for x[0]: h = x[0] if j = true: first = '' elif h = '9' first = 'ninety ' elif h = '8' first = 'eighty ' elif h = '7' first = 'seventy ' elif h = '6' first = 'sixty ' elif h = '5' first = 'fifty ' elif h = '4' first = 'fourty ' elif h = '3' first = 'thirty ' elif h = '2' first = 'twenty ' </code></pre>
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    1. USjerry2144
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    1. COThis looks like homework. Learn how to use the modulus operator % . (Also known as remainder division)
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    2. COAll for-loops in Python need to have `in` with them. `for x[3:5]:` will blow up. It should be: `for var in x[3:5]:` (I just picked the name `var`). Furthermore, you use `==` for comparison tests, not `=` (which is for variable assignment).
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    3. CONoticed this- http://stackoverflow.com/questions/8982163/how-do-i-tell-python-to-convert-integers-into-words -- seems like there is a pynum2word module out there. `import num2word` and then `print num2word.to_card(10675.78)`. Otherwise, I'd avoid these if-elif clusters and go for a lookup table. IE, tens = { 10: 'ten', 11: 'eleven' ... } and match it that way.
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