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    <p>Unfortunately, you are trying to find the values of <code>t</code> associated with a <code>y</code>, and your function is not monotonic so we need to actually code up a mock linear interpolation. Note, there may be a better way, but I do not know of it right now. Try the following code where <code>yVals</code> are the values you want an associated <code>t</code> for, and <code>possArray</code> will include all values of <code>t</code> that may satisfy those conditions. </p> <pre><code>clc; close all; clear all; t = [0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 105 110 115 120 125 130 135 140 145 150 155 160 165 170 175 180]; y = [0 5 9 19 25 32 46 65 79 90 100 115 123 141 153 159 160 171 181 185 193 200 205 211 215 220 223 222 225 224 228 231 231 228 235 234 231]; plot(t,y) grid on hold on yVals = [18.1,33,70,222.5,230]; possArray = cell(1,numel(yVals)); iter = 1; for val = yVals; poss = []; possNum = 1; for i = 1:numel(y)-1 if y(i) &lt;= val &amp;&amp; y(i+1) &gt;= val minDiff = val-y(i); yDiff = y(i+1)-y(i); percAlong = minDiff/yDiff; poss(possNum) = (t(i+1)-t(i))*percAlong+t(i); possNum = possNum+1; end end possArray{iter} = poss; iter = iter + 1; end colors = hsv(numel(yVals)); legendCell = cell(numel(yVals)+1,1); legendCell{1} = 'Original Line'; for i = 1:numel(yVals) plot(possArray{i},yVals(i)*ones(size(possArray{i})),... 'x','MarkerSize',10,'LineWidth',2,'Color',colors(i,:)) legendCell{i+1} = ['Values for Y = ' ,num2str(yVals(i))]; end legend(legendCell) hold off </code></pre> <p>As stated previously, this is linear interpolation, so if you need it to be more complicated that is on you, the concept should however be similar</p> <p><strong>UPDATE</strong> </p> <p>Updated code above to be a little more clean, and added a plot indicating that multiple possibilities may arise for a single value, and that the code will return all possibilities. </p>
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    1. COThanks for the solution it does a wonderful job for me !
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    2. CO+1 for the time taken writing this
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    3. CO@MarianZlatev No problem. Please do take the time to understand how it works. Whether it is a homework problem or not, it is always a good idea to analyze these sorts of things so that you are more well equipped later and can come up with some creative solutions for future problems
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