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2013-10-10T06:43:50.967
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You can check the type in GHCi with <code>:t</code>, as mentioned in the other answers. If you want to try figuring it out yourself, you need to substitute the types as appropriate. In your first example, we have <pre><code>zipWith :: (a -> b -> c) -> [a] -> [b] -> [c] </code></pre> and <pre><code>map :: (a -> b) -> [a] -> [b] </code></pre> The first argument of <code>map</code> is a function of one argument, so we have to regard <code>zipWith</code> as such a function: <pre><code>zipWith :: (a -> b -> c) -> ([a] -> [b] -> [c]) </code></pre> (The type above is equivalent to the original one. It means <code>zipWith</code> converts a function which takes arguments of types <code>a</code> and <code>b</code> to a function which takes lists of <code>a</code> and <code>b</code>.) <code>map</code> can be seen as a function of one argument as well: <pre><code>map :: (a -> b) -> ([a] -> [b]) </code></pre> Now, we fill in the types in <code>map</code>'s result type - <code>a</code> becomes <code>a -> b -> c</code> and <code>b</code> becomes <code>[a] -> [b] -> [c]</code>: <pre><code>map zipWith :: [a -> b -> c] -> [[a] -> [b] -> [c]] </code></pre> P.S.: Do you really want functions which take lists of functions as arguments? If you just want to zip two lists adding the corresponding elements you want <pre><code> zipWith (+) :: Num c => [c] -> [c] -> [c] </code></pre> rather than <code>zipWith sum</code>.
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