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    <p>As you are not interested in STL containers(although I would advice you to look into it for eg <code>vector</code>), declare an array of whatever maximum size you want</p> <pre><code>int arr[10]; </code></pre> <p>Now access the elements in an array through indexing and assign the value</p> <pre><code>arr[0] = 5; //indexes start from 0 and in this case till 9 </code></pre> <p>Or keep a variable for index as</p> <pre><code>int index = 0; </code></pre> <p>While inserting, use:</p> <pre><code>arr[index] = value; index++; </code></pre> <p>While making an element in array available, just decrement the index to point that the later indexes are free to be filled.</p> <p>EDIT:</p> <p>See the code below:</p> <pre><code>#include&lt;iostream&gt; using namespace std; int main() { int arr[10]; int choice; int num; int index = 0; do { cout&lt;&lt;"enter you choice:\n"; cout&lt;&lt;"1. add number\n"; cout&lt;&lt;"2. delete number\n"; cout&lt;&lt;"3. display memory\n"; cout&lt;&lt;"anything else to exit\n"; cin&gt;&gt;choice; switch(choice) { case 1: if(index==10) { cout&lt;&lt;"no more space available\n"; } else { cout&lt;&lt;"enter number: "; cin&gt;&gt;num; arr[index++] = num; } break; case 2: if(index==0) { cout&lt;&lt;"memory empty\n"; } else { cout&lt;&lt;"item deleted!\n "; index--; } break; case 3: for(int i = 0;i&lt;index;i++) { cout&lt;&lt;arr[i]&lt;&lt;'\t'; } cout&lt;&lt;endl; break; default: cout&lt;&lt;"exiting......."; } }while(choice&gt;0 &amp;&amp; choice&lt;4); } </code></pre>
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    1. POinsert and delete integers on the fly
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    1. COcan you show me a simple function that inserts and also remembers the index so if the user inserts another number again it doesnt override arr[0]
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    2. COi tried this and it didnt work http://pastebin.com/6wYtuu58
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    3. CO@Mr.1.0 rather than functions, you should consider writing a class that holds both the array and the current index.
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