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  1. PO
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    <p>First I can't reproduce the mac results using python2.7.1 and beautifulsoup4.3.2, that is I am getting the extra semicolon on all systems.</p> <p>The easy fix is a) use strictly valid HTML, or b) add a space after the ampersand. Chances are you can't change the source, and if you could parse out and replace these in python you wouldn't be needing BeautifulSoup ;)</p> <p>So the problem is that the BeautifulSoupHTMLParser first converts <code>S&amp;P500</code> to <code>S&amp;P500;</code> because it assumes <code>P500</code> is the character name and you just forgot the semicolon.</p> <p>Then later it reparses the string and finds <code>&amp;P500;</code>. Now it doesn't recognize <code>P500</code> as a valid name and converts the <code>&amp;</code> to <code>&amp;amp;</code> without touching the rest.</p> <p>Here is a stupid monkeypatch <strong>only to demonstrate my point</strong>. I don't know the inner workings of BeautifulSoup well enough to propose a proper solution.</p> <pre><code>from bs4 import BeautifulSoup from bs4.builder._htmlparser import BeautifulSoupHTMLParser from bsp.dammit import EntitySubstitution def handle_entityref(self, name): character = EntitySubstitution.HTML_ENTITY_TO_CHARACTER.get(name) if character is not None: data = character else: # Previously was # data = "&amp;%s;" % name data = "&amp;%s" % name self.handle_data(data) html = '&lt;td&gt;S&amp;P500&lt;/td&gt;' # Pre monkeypatching # &lt;td&gt;S&amp;amp;P500;&lt;/td&gt; print(BeautifulSoup(html)) BeautifulSoupHTMLParser.handle_entityref = handle_entityref # Post monkeypatching # &lt;td&gt;S&amp;amp;P500&lt;/td&gt; print(BeautifulSoup(html)) </code></pre> <p>Hopefully someone more versed in bs4 can give you a proper solution, good luck.</p>
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    1. POPython BeautifulSoup Ampersand issue Mac vs. Linux Ubuntu
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    1. USkalhartt
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    1. COthanks, useful - there does seem to be different behaviour b/w systems, see: [link](http://stackoverflow.com/questions/18515986/beautifulsoup-in-python-not-parsing-right?rq=1)
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    2. COIt's very possible, but that link in particular appears to be an encoding issue. Ampersand is in the ascii set, so those issues shouldn't affect this example.
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    3. COI guess brute force would be to create a dictionary of ascii characters and their numerical code / shortcut code - then do search for all ampersand characters, if they're not followed by characters which make a code, replace the & by &amp;
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